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2 years ago

What are the solutions of the quadratic equation 0 = 4(x - 3)2 - 16?

Mathematics

1 answer:

erastovalidia [21]2 years ago

8 0

Answer:

x = 5, x = 1

Step-by-step explanation:

The quadratic equation 0 = 4(x - 3)2 - 16.

Using binomial theorem, (a - b)2 = a2 - 2ab + b2 to expand (x - 3)2.

0 = 4(x2 - 6x + 9 ) - 16.

Using distributive property to multiply 4 by x2 - 6x + 9.

0 = 4x2 - 24x + 36 - 16.

Subtract 16 from 36 to get 20.

0 = 4x2 - 24x + 20.

4x2 - 24x + 20 = 0.

Divide both sides by 4.

x2 - 6x + 5 = 0.

To solve the equation, factor and rewrite as x2 + ax + bx + 5

a + b = -6, ab = 1(5) = 5.

a = -5, b = -1.

Rewriting x2 - 6x + 5 as

(x2 - 5x) + (-x + 5)

Factor x in the first and -1 in the second group.

x(x - 5) - (x - 5)

Factor out common term

(x - 5)(x - 1)

By solving the above, we get

x = 5, x = 1

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I hope this helped!

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now, we can find nth term

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