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Nuetrik [128]
3 years ago
6

I need help with these four problems.. anyone??

Physics
1 answer:
babunello [35]3 years ago
8 0
1) 14g
2) 24 fl oz
3)10 cups
4)12 and 1/2 cups
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Can I PLEASE get some help? I REALLY need it!
soldi70 [24.7K]
The answer is C. Hope this helps.
7 0
3 years ago
Suppose there is a sample of xenon in a sealed rectangular container. The gas exerts a total force of 6.05 N perpendicular to on
shtirl [24]

Answer:

<h2> 0.147136N/m²</h2>

Explanation:

Pressure is defines as force exerts by a body per its unit area.

Pressure = Force/Area

Given the total force exerted by the gas = 6.05N

Area of the rectangular container = 0.121 m * 0.201 m = 0.024321m²

Pressure of the sample = 6.05/0.02432

Pressure of the sample = 0.147136N/m²

6 0
3 years ago
5. Describe the sequence of mechanical
butalik [34]

Answer: idk that is a tough one!

Explanation: that is a hard question IDK

5 0
3 years ago
If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the
Serjik [45]
The first law of thermodynamics states the conservation of energy and heat where the total energy in an isolated system may be transformed into another, but never created or destroyed. If 314 J of energy was released to the room, then also 314 J of energy was also removed from food in that refrigerator assuming it is an isolated system. <span>
</span>
7 0
3 years ago
Find an expression for the kinetic energy of the car at the top of the loop.Express the kinetic energy in terms of m, g, h, and
lyudmila [28]

Answer:

K.E₂ = mg(h - 2R)

Explanation:

The diagram of the car at the top of the loop is given below. Considering the initial position of the car and the final position as the top of the loop. We apply law of conservation of energy:

K.E₁ + P.E₁ = K.E₂ + P.E₂

where,

K.E₁ = Initial Kinetic Energy = (1/2)mv² = (1/2)m(0 m/s)² = 0 (car initially at rest)

P.E₁ = Initial Potential Energy = mgh

K.E₂ = Final Kinetic Energy at the top of the loop = ?

P.E₂ = Final Potential Energy = mg(2R) (since, the height at top of loop is 2R)

Therefore,

0 + mgh = K.E₂ + mg(2R)

<u>K.E₂ = mg(h - 2R)</u>

3 0
3 years ago
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