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3 years ago

13

Moon problem please help!

2 answers:

CaHeK987 [17]3 years ago

6 0

Answer: crescent moon

Mariulka [41]3 years ago

4 0

Answer:

crescent Moon crescent Moon

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In amplitude modulation, which wave property remains constant?

NNADVOKAT [17]

The carrier frequency remains constant during amplitude modulation. :)

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3 years ago

Kilo- - 1,000<br>deka- - 10<br><br>How much larger is a kilo- than a deka-?

Ilya [14]

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3 years ago

Four electrons are located at the corners of a square 10.0 nm on a side, with an alpha particle at its midpoint. How much work i

Elis [28]

Four electrons are placed at the corner of a square

So we will first find the electrostatic potential at the center of the square

So here it is given as

$V = 4\frac{kQ}{r}$

here

r = distance of corner of the square from it center

$r = \frac{a}{\sqrt2}$

$r = \frac{10nm}{\sqrt2} = 7.07 nm$

$Q = e = -1.6 * 10^{-19} C$

now the net potential is given as

$V = \frac{4 * 9*10^9 * (-1.6 * 10^{-19})}{7.07 * 10^{-9}}$

$V = 0.815 V$

now potential energy of alpha particle at this position

$U_i = qV = 2*1.6 * 10^{-19} * (-0.815) = -2.6 * 10^{-19} J$

Now at the mid point of one of the side

Electrostatic potential is given as

$V = 2\frac{kQ}{r_1} + 2\frac{kQ}{r_2}$

here we know that

$r_1 = \frac{a}{2} = 5 nm$

$r_2 = \sqrt{(a/2)^2 + a^2} = \frac{\sqrt5 a}{2}$

$r_2 = 11.2 nm$

now potential is given as

$V = 2\frac{9 * 10^9 * (-1.6 * 10^{-19})}{5 * 10^{-9}} + 2\frac{9*10^9 * (-1.6 * 10^{-19})}{11.2 * 10^{-9}}$

$V = -0.576 - 0.257 = -0.833 V$

now final potential energy is given as

$U_f = q*V = 2*1.6 * 10^{-19}* (-0.833) = -2.67 * 10^{-19} J$

Now work done in this process is given as

$W = U_f - U_i$

$W = (-0.267 * 10^{-19}) - (-0.26 * 10^{-19}}$

$W = -7 * 10^{-22} J$

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3 years ago

What happens to a light if the switch is turned off in the circuit?

lukranit [14]

In a parallel circuit nothing happens. All the other lights stay on but if it was a series circuit ALL the lights would turn off at one time.

If there is an ABCD question I can answer that but I wasn't sure so I just said this

Hope it is helpful :)

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3 years ago

a crane lifts a 75 kg mass at a height of 8m. calculate the gravitational potential energy gained by the mass (g= 10N)

Leno4ka [110]

Answer:

6000 J

Explanation:

Potential energy = mass*gravity*height (U = m*g*h)

In this case g = 10 so

U = 75*10*8 = 6000 J (joules) [kg * m^2/s^2]

7 0

3 years ago