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3 years ago

Artistic works in the animal style often contain ________ and images of abstracted animals.

1 answer:

5 0

The answer to the above question is "Interlace".

Artistic works in the animal style often contain INTERLACE and images of abstracted animals. In the medieval art, this artistic work contains decorative elements. Some elements are knotted while others are braided.

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A 70.0-kg person throws a 0.0480-kg snowball forward with a ground speed of 33.5 m/s. A second person, with a mass of 55.0 kg, c

saw5 [17]

Answer:

The final velocity of the thrower is $\bf{3.88~m/s}$ and the final velocity of the catcher is $\bf{0.029~m/s}$ .

Explanation:

Given:

The mass of the thrower, $m_{t} = 70~Kg$ .

The mass of the catcher, $m_{c} = 55~Kg$ .

The mass of the ball, $m_{b} = 0.0480~Kg$ .

Initial velocity of the thrower, $v_{it} = 3.90~m/s$

Final velocity of the ball, $v_{fb} = 33.5~m/s$

Initial velocity of the catcher, $v_{ic} = 0~m/s$

Consider that the final velocity of the thrower is $v_{ft}$ . From the conservation of momentum,

$&& m_{t}v_{ft} + m_{b}v_{fb} = (m_{t} + m_{b})v_{it}\\&or,& v_{ft} = \dfrac{(m_{t} + m_{b})v_{it} - m_{b}v_{fb}}{m_{t}}\\&or,& v_{ft} = \dfrac{(70 + 0.0480)(3.90) - (0.0480)(33.5)}{70}\\&or,& v_{ft} = 3.88~m/s$

Consider that the final velocity of the catcher is $v_{fc}$ . From the conservation of momentum,

$&& (m_{c} + m_{b})v_{fc} = m_{b}v_{it}\\&or,& v_{fc} = \dfrac{m_{b}v_{it}}{(m_{c} + m_{b})}\\&or,& v_{fc} = \dfrac{(0.048)(33.5)}{(55.0 + 0.0480)}\\&or,& v_{fc} = 0.029~m/s$

Thus, the final velocity of thrower is $3.88~m/s$ and that for the catcher is $0.029~m/s$ .

8 0

3 years ago

Which best describes the forces identified by Newton’s third law of motion?

egoroff_w [7]

<span>equal and acting on different objects</span>

4 0

3 years ago

Read 2 more answers

Diamonds are usually found in pipes 50 to 200 m across made of ________.

Leokris [45]

I believe the correct answer would be kimberlite. Diamonds are usually found in pipes 50 to 200 m across made of kimberlite. It is an igneous rock that is known to contain traces of diamonds. It is named base on the town where it was discovered which is Kimberley, South Africa.

7 0

3 years ago

A circuit contains a single 270-pf capacitor hooked across a battery. it is desired to store four times as much energy in a comb

yan [13]

The energy stored by a system of capacitors is given by
$U= \frac{1}{2}C_{eq} V^2$
where Ceq is the equivalent capacitance of the system, and V is the voltage applied.

In the formula, we can see there is a direct proportionality between U and C. This means that if we want to increase the energy stored by 4 times, we have to increase C by 4 times, if we keep the same voltage.

Calling $C_1 = 270 pF$ the capacitance of the original capacitor, we can solve the problem by asking that, adding a new capacitor with $C_x$ , the new equivalent capacitance of the system $C_{eq}$ must be equal to $4C_1$ . If we add the new capacitance X in parallel, the equivalent capacitance of the new system is the sum of the two capacitance
$C_{eq} = C_1 + C_x$
and since Ceq must be equal to 4 C1, we can write
$C_1+C_x = 4C_1$
from which we find
$C_x=3C_1=3 \cdot 270 pF=810 pF$

5 0

3 years ago

An iron wire has a cross-sectional area equal to 5.00×10⁻⁶ m² . Carry out the following steps to determine the drift speed of th

Doss [256]

In mass, there are 55.85 × 10⁻³ kg/mol in in 1 mole of iron.
The molar density of iron is equal to 1.41 × 10⁵ mol/m³.
The density of iron atoms is equal to 8.49 × 10²⁸ atoms/m³.
The number density of conduction electrons is equal to 1.70 × 10²⁹ conduction electrons/m³.
The drift speed of conduction electrons is equal to 2.21 × 10⁻⁴ m/s.

<h3>How to calculate the drift speed of the conduction electrons?</h3>

Mathematically, the drift speed of the conduction electrons can be calculated by using this formula:

V = (m × σ × V)/ρ × e × f × l)

V = I/(n × A × Q)

Where:

U represents the drift speed of the conduction electrons, in m/s.

m represents the molecular mass of the metal, in kg.

e represents the elementary charge, in C.

f represents the number of free electrons per atom.

σ represents the electric conductivity of the medium at a particular temperature in S/m.

ρ represents the density of the conductor, in kg/m³.

ℓ represents the length of the conductor, in m.

ΔV represents the voltage applied or potential difference across the conductor in V.

<h3>How many kilograms are there in 1 mole of iron? </h3>

Molar mass of iron = 55.85 g/mol.

In Kilograms, we have:

Mass = 55.85 × 1/1000

Mass = 55.85 × 10⁻³ kg/mol.

For the molar density of iron, we have:

Molar density = density/molar mass

Molar density = 7874/0.056

Molar density = 1.41 × 10⁵ mol/m³.

For the density of iron atoms, we have:

Density of iron atoms = Avogadro's constant × molar density

Density of iron atoms = 6.023 × 10²³ × 1.406 × 10⁵

Density of iron atoms = 8.49 × 10²⁸ atoms/m³.

For the number density of conduction electrons, we have:

Fe ---> Fe²⁺ + 2e⁻

Number density of conduction electrons = 2 conduction electrons/1 atom of iron

Number density of conduction electrons = 2 × 8.49 × 10²⁸

Number density of conduction electrons = 1.70 × 10²⁹ conduction electrons/m³.

For the drift speed of conduction electrons, we have:

V = I/(n × A × Q)

V = 30/(1.70 × 10²⁹ × 1.602 × 10⁻¹⁹ × 5 × 10⁻⁶)

Drift speed, V = 2.21 × 10⁻⁴ m/s.

Read more on drift speed here: brainly.com/question/15219891

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Complete Question:

An iron wire has a cross-sectional area of 5.00 x 10-6 m2. Carry out steps (a) through (e) to compute the drift speed of the conduction electrons in the wire.

(a) How many kilograms are there in 1 mole of iron?

(b) Starting with the density of iron and the result of part (a), compute the molar density of iron (the number of moles of iron per cubic meter).

(d) Obtain the number density of conduction electrons given that there are two conduction electrons per iron atom.

(e) If the wire carries a current of 30.0 A, calculate the drift speed of conduction electrons.

4 0

2 years ago