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3 years ago

Where can classic examples of shield volcanoes be found?

1 answer:

4 0

The largest is Mauna Loa on the Big Island of Hawaii; all the volcanoes in the Hawaiian Islands are shield volcanoes. There are also shield volcanoes, for example, in Washington, Oregon, and the Galapagos Islands

You might be interested in

Which type of pollution occurs when small particles of soil are suspended in water?

vova2212 [387]

The type of pollution when small particles of soil are suspended in the water is called Suspended Matter Pollution. <span>This type of pollution happens when soil enter the water and do not mix in with the water molecules.</span>

7 0

3 years ago

Read 2 more answers

Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.55 times a second. A tack is stuck in the tire a

earnstyle [38]

Answer:

Tangential speed = 5.72 m/s

Centripetal acceleration = $91.6\text{ m/s}{}^2$

Explanation:

The tangential speed, V, is given by

$v=\omega r$

where $\omega$ is the angular speed and is given by $2\pi f$ (f is the angular frequency or frequency of rotation)

Thus,

$v=2\pi f r = 2\times3.14\times2.55\times0.357 = 5.72\text{ m/s}$

The centripetal acceleration,a, is given by

$a=\dfrac{v^2}{r}$

$a=\dfrac{5.72^2}{0.357} = 91.6\text{ m/s}{}^2$

7 0

4 years ago

Read 2 more answers

A closed curve encircles several conductors. The line integral around this curve is (image attached below)

Masteriza [31]

The net current in the conductors and the value of the line integral

$I=\frac{3.2\cdot 10^{-4}}{4\pi \cdot 10^{-7}}=254.77\, A$
The resultant remains same 3.2 *10^4 Tm

This is further explained below.

<h3>What is the net current in the conductors?</h3>

Generally,

To put it another way, the total current In flowing across a surface S (contained by C) is proportional to the line integral of the magnetic B-field (in tesla, T).

$\oint_C \mathbf{B} \cdot \mathrm{d}\boldsymbol{\ell} = \mu_0 \iint_S \mathbf{J} \cdot \mathrm{d}\mathbf{S} = \mu_0I_\mathrm{enc}$

$I=\frac{3.2\cdot 10^{-4}}{4\pi \cdot 10^{-7}}=254.77\, A$

In conclusion, It is possible for the line integral to go around the loop in either direction (clockwise or counterclockwise), the vector area dS to point in either of the two normal directions and Ienc, which is the net current passing through the surface S, to be positive in either direction—but both directions can be chosen as positive in this example. The right-hand rule solves these ambiguities.

The resultant remains the same at 3.2 *10^4 Tm

Read more about conductors

brainly.com/question/8426444

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5 0

2 years ago

A marble dropped in still water will create circular ripples or waves. the radius of each circular wave will increase 4 centimet

Gnom [1K]

The circumference of the circle after t seconds = 25.12 t

Given data,

The radius of each circular wave will increase by four centimeters per second (cm/s)

In 1 second of circular wave radius = 4cm

In 1*t second of circular wave radius = 4t cm

As a result, the radius of the circular wave after t seconds is 4t cm.

We already know that the circumference of a circle is given by = 2πr, where r is the circle's radius.

As a result, the radius of a circular wave after t seconds is = 2π * radius of a circular wave after t seconds = 2π * 4t

= 8πt

( Taking π = 3.14 )

As a result, the circumference of the circle after t seconds = 8πt

= 3.14t

= 25.12t

Find more on circumference at : brainly.in/question/49774764

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5 0

2 years ago

If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation w

Elina [12.6K]

The answer is letter C.

Weight (on Earth) is the force due to the mass of Earth attracting whatever mass is subject of discussion.

The force of attraction between any two masses is called Newton's Law of Universal Gravitation:

$G \frac{m_1m_2}{d^2}$

$G$ is simply a given constant.

If we're at the surface of Eath, $m_1$ refers to the mass of the Earth, $m_2$ to the mass of whatever is on the surface of Earth, and $d$ to the radius of Earth.

Normally, we define a constant $g$ to be equal to $G \frac{M}{r^2}$ ; in which $M$ is the mass of Earth and $r$ the radius of earth; $g$ happens to be around 9.8.

By that, we adapt the Law of Universal Gravitation to objects on the surface of Earth, we call that force Weight.

$W=mg$

As you can see, weight is directly proportional to mass, more mass implies more weight.

8 0

4 years ago