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3 years ago

Where can classic examples of shield volcanoes be found?

1 answer:

4 0

The largest is Mauna Loa on the Big Island of Hawaii; all the volcanoes in the Hawaiian Islands are shield volcanoes. There are also shield volcanoes, for example, in Washington, Oregon, and the Galapagos Islands

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A cat leaps into the air to catch a bird with an initial speed of 2.74 m/s at an angle of 60.0° above the ground. What is the hi

Volgvan

Answer: D. 0.29 m

Explanation:

We will use the following equations to describe the leap of the cat:

$y=V_{o}sin\theta t-\frac{gt^{2}}{2}$ (1)

$V_{y}=V_{oy}-gt$ (2)

Where:

$y$ is the height of the cat

$V_{oy}=V_{o}sin\theta$ is the cat's initial velocity

$\theta=60\°$

$g=9.8m/s^{2}$ is the acceleration due gravity

$t$ is the time

$V_{y}$ is the y-component of the velocity

Now the cat will have its maximum height $y_{max}$ when $V_{y}=0$ . So equation (2) is rewritten as:

$0=V_{oy}-gt$ (3)

Finding $t$ :

$t=\frac{V_{oy}}{g}=\frac{V_{o}sin\theta}{g}$ (4)

$t=\frac{2.74 m/s sin(60\°)}{9.8m/s^{2}}$ (5)

$t=0.24 s$ (6)

Substituting (6) in (1):

$y_{max}=(2.74 m/s)sin(60\°) (0.24 s)-\frac{(9.8m/s^{2})(0.24 s)^{2}}{2}$ (7)

Finally:

$y_{max}=0.287 m \approx 0.29 m$ (8)

3 0

3 years ago

In a wire with a 1.05 mm2 cross-sectional area, 7.93×1020 electrons flow past any point during 3.97 s. What is the current ????

34kurt

Answer:

The current in the wire is 31.96 A.

Explanation:

The current in the wire can be calculated as follows:

$I = \frac{q}{t}$

Where:

q: is the electric charge transferred through the surface

t: is the time

The charge, q, is:

$q = n*e$

Where:

n: is the number of electrons = 7.93x10²⁰

e: is the electron's charge = 1.6x10⁻¹⁹ C

$q = n*e = 7.93 \cdot 10^{20}*1.6 \cdot 10^{-19} C = 126.88 C$

Hence, the current in the wire is:

$I = \frac{126.88 C}{3.97 s} = 31.96 A$

Therefore, the current in the wire is 31.96 A.

I hope it helps you!

3 0

3 years ago

If an automobile battery is rated at 20 ampere-hours, what is the maximum current that can be supplied for 19 minutes?

Elenna [48]

20Ah is the number of charge that can be supplied at 20A for 1 hour. If you wish to drain it in 19 minutes, then the current is:
$20*60 = A_{2}*19$
$A_{2}=63.2A$

5 0

2 years ago

In this problem, you will practice applying this formula to several situations involving angular acceleration. in all of these s

MatroZZZ [7]

A- 2*[(m1 - m2)/(m1 + m2)]*g/L The rotation is in the counterclockwise direction and the angular acceleration is positive. B- 2*[(m1 - m2)/(m1+ m2 +mbar/3)]*g/L The rotation is in the counterclockwise direction and the angular acceleration is positive.

6 0

3 years ago

A radioactive nuclide of atomic number emits an electron, then the daughter nuclide emits a gamma ray. What is the atomic number

Galina-37 [17]

Answer:

correct answer is b Z --->Z+1

Explanation:

In the processes of radioactive decay there are three basic processes the emission of alpha particles and the emission of beta rays and the emission of ayos range

The emission of a beta ray implies the transformation of a neutral into a proton, which implies the increase of the atomic number in a unit

Z ----> Z +1

the atomic mass does not change since the mass of the two particles is practically the same, to balance the reaction antineutrino must also be emitted

The daughter particle is in an execrated state and passes to its base state with the emission of a gamma ray that does not change its atomic number or its atomic mass.

Consequently, from the above the correct answer is b

3 0

3 years ago