let's firstly convert the mixed fraction to improper fraction, and then divide.
![\bf \stackrel{mixed}{11\frac{1}{2}}\implies \cfrac{11\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{23}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{23}{2}\div \cfrac{3}{4}\implies \cfrac{23}{2}\cdot \cfrac{4}{3}\implies \cfrac{23}{3}\cdot \cfrac{4}{2}\implies \cfrac{23}{3}\cdot 2\implies \cfrac{46}{3}\implies 15\frac{1}{3}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B11%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B11%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B23%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B23%7D%7B2%7D%5Cdiv%20%5Ccfrac%7B3%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B23%7D%7B2%7D%5Ccdot%20%5Ccfrac%7B4%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B23%7D%7B3%7D%5Ccdot%20%5Ccfrac%7B4%7D%7B2%7D%5Cimplies%20%5Ccfrac%7B23%7D%7B3%7D%5Ccdot%202%5Cimplies%20%5Ccfrac%7B46%7D%7B3%7D%5Cimplies%2015%5Cfrac%7B1%7D%7B3%7D)
Find the slope m.
Use the point-slope formula.
Solve for y.
b is an ipotenuse, so b > a and 2a+b>3a
So what we do is
area that remains=total area-triangle area that was cut out
we need to find 2 things
total area
triangle area
total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12
triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4
so
total area=6x^2+17x+12
triangle area=x^2-4
subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16
area that remains is 5x^2+17x+16
Answer:
≅ 0.02083333
Step-by-step explanation:
(3.5 * 2/7 - 2/3)÷16 = 1
48
≅ 0.02083333
1: Conversion a decimal number to a fraction: 3.5
2: Multiple: 3.5 * 2
7
= 7 · 2
2 · 7
= 14
14
= 1 · 14
1 · 14
= 1
3: Subtract:
4: Divide
<em><u>Hope this helps.</u></em>
