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mafiozo [28]
4 years ago
10

Find two numbers with a sum of 20 and a difference of 14.

Mathematics
1 answer:
lutik1710 [3]4 years ago
4 0
The answers are 17 and 3

17 - 3 = 14
17 + 3 = 20
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Three horses, call them a, b, and c, are going to race against each other. the probability that a will win the race is 1⁄5 and t
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3 years ago
4x + y = 3 -2x + 3y = -19 what's the solution plz help
Rainbow [258]

The solution to given system of equations is x = 2 and y = -5

<em><u>Solution:</u></em>

<em><u>Given the system of equations are:</u></em>

4x + y = 3 ---------- eqn 1

-2x + 3y = -19 ---------- eqn 2

We have to find the solution to above system of equations

<em><u>We can solve the system by substitution method</u></em>

From eqn 1,

4x + y = 3

Isolate y to one side

y = 3 - 4x ----------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

-2x + 3(3 - 4x) = -19

-2x + 9 - 12x = -19

Combine the like terms

-14x = -19 - 9

-14x = -28

Divide both sides of equation by -14

<h3>x = 2</h3>

<em><u>Substitute x = 2 in eqn 3</u></em>

y = 3 - 4(2)

y = 3 - 8

<h3>y = -5</h3>

Thus the solution is x = 2 and y = -5

5 0
3 years ago
if a company has 150 shares of common stock ans $15,000.00 to be distributed to its holders, how much would each share receive?
Yuri [45]
C. 1oo because 100 * 150 = 15000
7 0
4 years ago
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PLEASE HELP ASAP
Lerok [7]

Answer:

A) 2(9x - 2)

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The greatest common factor of 18x and -4 is 2.

B is wrong because 18 is not the greatest common factor of both, since 4 cannot be divided by 18 and result in a whole number.

C is wrong because 18x cannot be divided by 4 to produce a whole number.

D is wrong because it restates the problem in a different way, therefore not factoring it completely. 1 is a common factor of both, but not the greatest.

4 0
3 years ago
What value of x is in the solution set of 8x – 6 &gt; 12 + 2x?
Harman [31]

Answer:

8x - 6 > 12 + 2x \\ 8x - 2x > 12 + 6 \\ 6x > 18 \\  \frac{6x}{6}  >  \frac{18}{6}  \\ x > 3

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>!</em>

3 0
3 years ago
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