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SSSSS [86.1K]
3 years ago
6

"Give an explanation of the combustion reaction of octane."

Chemistry
1 answer:
SIZIF [17.4K]3 years ago
6 0

Thus we can balance the oxygen atoms by putting a prefix of 25/2 on the left side. To obtain a equation containing whole numbers, we multiply the entire equation by 2. This gives the final equation. 2 C8H18 + 25 O2 ---> 16 CO2 +18 H2O.

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Balance these equations:
MatroZZZ [7]

Explanation:

H² + Br² = 2HBr

2Mg + O² = 2MgO

2H² + O² = 2H²O

hope this helps you

6 0
3 years ago
Read 2 more answers
Would you expect an atom to have a charge?
puteri [66]

Answer:

An atom consists of a positively charged nucleus, surrounded by one or more negatively charged particles called electrons. The positive charges equal the negative charges, so the atom has no overall charge; it is electrically neutral.

4 0
1 year ago
How many grams of chlorine gas are present in a 150. liter cylinder of chlorine held at a pressure of 1.00 atm and 0. °C? Group
OlgaM077 [116]

Answer:

474 grams of chlorine gas are present in a 150 liter cylinder of chlorine held at a pressure of 1.00 atm and 0 °C

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

  • P= 1.00 atm
  • V= 150 L
  • n= ?
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= 0 C= 273 K

Replacing:

1.00 atm* 150 L= n*0.08206 \frac{atm*L}{mol*K} *273 K

Solving:

n=\frac{1.00 atm* 150 L}{0.08206 \frac{atm*L}{mol*K}*273 K}

n= 6.69 moles

Being Cl= 35.45 g/mole, the molar mass of chlorine gas is:

Cl₂=2*35.45 g/mole= 70.9 g/mole

So if 1 mole has 70.9 grams, 6.69 moles of the gas, how much mass does it have?

mass=\frac{6.69 moles*70.9 grams}{1 mole}

mass= 474.321 grams ≅ 474 grams

<u><em>474 grams of chlorine gas are present in a 150 liter cylinder of chlorine held at a pressure of 1.00 atm and 0 °C</em></u>

4 0
3 years ago
A chemistry student was asked to calculate the number of moles of iron required to react with 1.20 mol of oxygen to produce iron
Delicious77 [7]

Answer:Write and balance the equation

4Fe + 3O2 -> 2Fe2O3

0.32 mol Fe x 2 mol Fe2O3 / 4 mol Fe =

0.16 mol of Fe2O3

Explanation:

8 0
3 years ago
Calculate pCl for the titration of 100.0mL of 0.1000 MCI with 0.1000 M
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the titration is the most important part in determining whether

4 0
3 years ago
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