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ololo11 [35]
3 years ago
12

Which of these pairs of elements have the same number of valence electrons?

Chemistry
2 answers:
Nezavi [6.7K]3 years ago
5 0

Answer : The correct option is, (B) sodium and potassium

Explanation :

Valence electrons : Valence electrons are those electrons which are present in the outermost shell of the element.

As we know that,

<u>Option (A) :</u>

Element = Hydrogen

Atomic number = Number of electrons = 1

The electronic configuration is, 1s^1

The number of valence electrons = 1

Element = Helium

Atomic number = Number of electrons = 2

The electronic configuration is, 1s^2

The number of valence electrons = 2

<u>Option (B) :</u>

Element = Sodium

Atomic number = Number of electrons = 11

The electronic configuration is, 1s^22s^22p^63s^1

The number of valence electrons = 1

Element = Potassium

Atomic number = Number of electrons = 19

The electronic configuration is, 1s^22s^22p^63s^23p^64s^1

The number of valence electrons = 1

<u>Option (C) :</u>

Element = Carbon

Atomic number = Number of electrons = 6

The electronic configuration is, 1s^22s^22p^2

The number of valence electrons = 4

Element = Oxygen

Atomic number = Number of electrons = 8

The electronic configuration is, 1s^22s^22p^4

The number of valence electrons = 6

<u>Option (D) :</u>

Element = Boron

Atomic number = Number of electrons = 5

The electronic configuration is, 1s^22s^22p^1

The number of valence electrons = 3

Element = Beryllium

Atomic number = Number of electrons = 4

The electronic configuration is, 1s^22s^2

The number of valence electrons = 2

From this we conclude that, the sodium and potassium are the elements have the same number of valence electrons.

Hence, the correct option is, (B)

KatRina [158]3 years ago
3 0
B) sodium and potassium (1 valence electron)
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8 0
3 years ago
At 338 mm hg and 72 c a sample of carbon monoxide gas occupies a volune of 0.225 L the gas transferred to a 1.50 L flask and the
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Answer:

P₂  = 0.09 atm

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

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Initial pressure = 338 mmHg (338/760 =0.445 atm)

Initial temperature = 72 °C (72 +273 = 345 K)

Final temperature = -15°C (-15+273 = 258 K)

Final volume = 1.50 L

Final pressure = ?

Solution:

P₁V₁/T₁ = P₂V₂/T₂

P₂ = P₁V₁ T₂/ T₁ V₂ 

P₂ = 0.445 atm × 0.225 L × 258 K / 345 K × 1.50 L

P₂  =  25.83 atm .L.  K  / 293 K . L

P₂  = 0.09 atm

7 0
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If motor bike travels 2.4 km in 5 min find it average velocity?​
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Answer:

28.8km/h

Explanation:

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2.4/0.0833

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3 0
3 years ago
What mass of sodium chloride (NaCl) forms when 7.5 g of sodium carbonate (Na2CO3) reacts with a dilute solution of hydrochloric
Gre4nikov [31]

 The mass of NaCl  formed  is 8.307  grams


<u><em> calculation</em></u>

step 1: write the equation  for reaction

Na₂CO₃  + 2HCl → 2 NaCl  +CO₂ +H₂O

Step 2: find the  moles of Na₂CO₃

moles = mass/molar mass

 The  molar mass of Na₂CO₃  is = (23 x2) + 12 + ( 16 x3) = 106 g/mol

moles  = 7.5 g/106 g/mol =0.071 moles

Step 3: use the  mole ratio to determine the  mole of NaCl

Na₂CO₃:NaCl  is  1:2  therefore the moles of NaCl =0.07  x2 =0.142 moles


Step 4:  calculate mass  of NaCl

mass= moles x molar mass

the molar  mass of NaCl= 23 +35.5 =58.5 g/mol

mass  = 0.142  moles x 58.5 g/mol =8.307  grams

8 0
3 years ago
Read 2 more answers
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