A committee of three men and two women can be formed from a group of nine men and eleven women in how many different ways.
1 answer:
Answer:
4620.
Step-by-step explanation:
The number of combinations of 3 men from 9
= 9!/(9-3)!3!
= 9*8*7/3*2*1
= 84 ways.
The number of combinations of 2 women from 11
= 11!/11-2)!2!
= 11*10/2*1
= 55 ways.
So the total number of ways of men and women in the committee
= 84*55
= 4620.
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