Answer:
Option D. ⁸⁵₃₆Kr
Explanation:
⁸⁵₃₅Br —> ⁰₋₁e + ?
Let ⁿₘZ represent the unknown.
Thus, the equation becomes:
⁸⁵₃₅Br —> ⁰₋₁e + ⁿₘZ
Next, we shall determine n, m and Z as follow:
85 = 0 + n
85 = n
Thus,
n = 85
35 = –1 + m
Collect like terms
35 + 1 = m
36 = m
Thus,
m = 36
ⁿₘZ => ⁸⁵₃₆Z = > ⁸⁵₃₆Kr
Thus, the equation:
⁸⁵₃₅Br —> ⁰₋₁e + ⁿₘZ
Becomes:
⁸⁵₃₅Br —> ⁰₋₁e + ⁸⁵₃₆Kr
And walk another 25m west
Both of them are Heterogeneous mixtures. They can both be separated into their compounds, but not down to the element.
Answer:
(a) 110 rev/ min
(b) 5/6
Explanation:
As per the conservation of linear momentum,
L ( initial ) = L ( final )
I' ω' = ( I' + I'' ) ωf
I' is the rotational inertia of first wheel and I'' is the rotational inertia of second wheel which is at rest.
(a)
So, ωf = I' ω' / ( I' + I'' )
As I'' = 5I'
ωf = I' ω' / ( I' + 5I' )
ωf = ω'/ 6
now we know ω' = 660 rev / min
therefore ωf = 660/6
= 110 rev/ min
(b)
Initial kinetic energy will be K'
K' = I'ω'² / 2
and final K.E. will be K'' = ( I' + I'' )ωf² / 2
K'' = ( I' + 5I' ) (ω'/ 6)²/ 2
K'' = 6I' ω'²/72
K'' = I' ω'²/ 12
therefore the fraction lost is
ΔK/K' = ( K' - K'' ) / K'
= {( I'ω'² / 2) - (I' ω'²/ 12)} / ( I'ω'² / 2)
= 5/6
Answer:
Explanation:
Using equations of motion:
(a)
v=u+at
∴0=19.4−8.57t
∴t=19.4/8.57
=2.3s
B. Using s= ut + 1/2 at²
19.4(2.3)-1/28.57(2.3)²
= 21.92rad