A. Advanced new safety features that get everyone home at night.
B. polarization
i hope that is correct
<span>32 mph
First, let's calculate the location of the particle at t=1, and t=4
t=1
s = 6*t^2 + 2*t
s = 6*1^2 + 2*1
s = 6 + 2
s = 8
t = 4
s = 6*t^2 + 2*t
s = 6*4^2 + 2*4
s = 6*16 + 8
s = 96 + 8
s = 104
So the particle moved from 8 to 104 over the time period of 1 to 4 hours. And the average velocity is simply the distance moved over the time spent. So:
avg_vel = (104-8)/(4-1) = 96/3 = 32
And since the units were miles and hours, that means that the average speed of the particle over the interval [1,4] was 32 miles/hour, or 32 mph.</span>
Answer:
a = 177.77 [m/s^2]
Explanation:
Este es un problema relacionado con la segunda ley de Newton. La cual nos dice que la sumatoria de fuerzas aplicada sobre un cuerpo debe ser igual al producto de la masa por la aceleración.
De esta manera tenemos:
F = m*a
F = fuerza = 80 [N]
m = masa = 0.45 [kg]
80 = 0.45 * a
a = 80 / 0.45
a = 177.77 [m/s^2]