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4 years ago

How does a wildfire impact a population of oak trees?

Physics

2 answers:

miss Akunina [59]4 years ago

8 0

Answer:

it impacts the tree form.

Wildfire o Northwest California oak woodlands would naturally be subjected to ... o Fire does not necessarily have a positive impact on growth or recruitment of.

Explanation:

Many species of mature oaks are relatively tolerant to fire. Oaks might replace pines, or drought-tolerant shrubland might take the place ... “Areas with low tree density could maintain droughts for some time because of the cyclical effect of ... diseased plants and removing them from the flora population.

Ivanshal [37]4 years ago

8 0

Answer:

it burns the tree into another form

Explanation:

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!!PLEASE ANSWER ASAP!!

ikadub [295]

Work done = force * distance
2m * 9.8
work done = 19.6 J

5 0

3 years ago

When a car accelerates from a standing start, the crash test dummy appears to be pressed backward into the seat cushion. Which o

Setler [38]

<u>Answer:</u>

Option: D. Gravity is pulling the crash test dummy in the direction the car is moving.

<u>Explanation: </u>

When a car accelerates from a standing start, the crash test dummy appears to be pressed backward into the seat cushion because the gravity is pulling the crash test dummy in the direction the car is moving.

Basically when the car is starting, the person inside is in static position and the car is going to move. So it is putting a force on the person to move on the same speed. But as the person is sitting static hence gravity is pulling him behind from moving. Hence, The dummy appears to be pressed backward.

7 0

3 years ago

A Plane has a takeoff speed of 150 m/s and requires 1500m to reach that speed. Determine the acceleration of the plane and the t

luda_lava [24]

1) Acceleration: $7.5 m/s^2$

The motion of the plane is a uniformly accelerated motion, so we can find its acceleration by using the suvat equation

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

Here we have

v = 150 m/s is the final velocity of the plane

u = 0 (it starts from rest)

a=?

s = 1500 m is the displacement

Solving for a, we find

$a=\frac{v^2-u^2}{2s}=\frac{150^2-0}{2(1500)}=7.5 m/s^2$

2. Time: 20 s

For this part of the problem, we can use another suvat equation:

$v=u+at$

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

Here we already know:

v = 150 m/s is the final velocity of the plane

u = 0 (it starts from rest)

$a=7.5 m/s^2$ (found in part 1)

Solving for t, we find the time taken for the plane to reach the final velocity of 150 m/s:

$t=\frac{v-u}{a}=\frac{150-0}{7.5}=20 s$

3 0

4 years ago

A moon orbits a planet every 42 hours with a mean orbital radius of .002819 AU. The mass of the moon is 8.932 x 1022 kg. Using N

Pepsi [2]

Answer:

The mass of the planet is $1.9407\times10^{27}\ kg$

Explanation:

Given that,

Time period = 42 hours = 151200 sec

Orbital radius = 0.002819 AU = 421716397.5 m

Mass of moon $m=8.932\times10^{22}\ kg$

We need to calculate the mass of the planet

Using Kepler’s third law

$T^2\propto a^3$

$T^2=\dfrac{4\pi^2}{G(M+m)}\times a^3$

Where, a = orbital radius

T = time period

G = gravitational constant

M = mass of moon

m = mass of planet

Put the value into the formula

$(151200)^2=\dfrac{4\pi^2}{6.673\times10^{-11}(8.932\times10^{22}+m)}\times(421716397.5)^3$

$(8.932\times10^{22}+m)=\dfrac{4\pi^2}{6.673\times10^{-11}}\times\dfrac{(421716397.5)^3}{(151200)^2}$

$(8.932\times10^{22}+m)=1.94087\times10^{27}$

$m=1.94087\times10^{27}-8.932\times10^{22}$

$m=1.9407\times10^{27}\ kg$

Hence, The mass of the planet is $1.9407\times10^{27}\ kg$

8 0

4 years ago

Why is water important in cells?

Makovka662 [10]

Because without water they wouldn't able to remove waste, bring in nutrients or move oxygen around. BTW there is a bout 65% of water in the adult human body.

4 0

3 years ago