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2 years ago

Which of the following is a correctly balanced reaction equation?

Chemistry

1 answer:

kompoz [17]2 years ago

6 0

Answer:

CaCl2 + 2NaOH -> 2NaCl + Ca(OH)2

Explanation:

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Hot water is poured into four cups made of different materials (foam, glass, metal, plastic).After one minute, which will feel t

Marta_Voda [28]

The answer to this is metal

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3 years ago

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CAN SOMEONE HELP ME?!?! IM CONFUSED

Sati [7]

Answer: Solar winds have an influence all the way to about 160 AU from the Sun. About how many kilometers is that?

24,000,000,000 km

48,000,000,000 km

240,000,000,000 km

480,000,000,000 km

Explanation:

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3 years ago

Tia has a sample of pure gold (Au). She weighed the sample and the result was 35.9 grams. Tia wants to determine the number of a

Gemiola [76]

First, find moles of gold given the mass of the sample:
(35.9g Au)/(197.0g/mol Au) = 0.182mol Au

Second, multiply moles of Au by Avogrado's number:
(0.182mol)(6.02 x10^23)= 1.10x10^23 atoms Au

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4 years ago

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When 0.5141 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.823 °C to 29.419 °C

natka813 [3]

Answer:

$\Delta_{r}U$ of the reaction is -6313 kJ/mol

$\Delta_{r}H$ of the reaction is -6312 kJ/mol

Explanation:

$Temperature\,\,change= \Delta U = 29.419-25.823 =3.506^{o}C$

$q_{cal}= C \times \Delta T$

$=5.861 \times 3.596 = 21.076\,kJ$

$q_{rxn}= -q_{cal}= -21.076\,kJ$

$\Delta_{r}U= -21.076 \times \frac{154}{0.5141}= -6313\, kJ/mol$

Therefore, $\Delta_{r}U$ of the reaction is -6313 kJ/mol.

The chemical reaction in bomb calorimeter is as follows.

$C_{12}H_{10}(s)+\frac{27}{2}O_{2}(g)\rightarrow 12CO_{2}(g)+5H_{2}O(g)$

$Number\,of\,moles\Delta n=(12+5)-\frac{27}{2}=3.5$

$\Delta_{r}H=\Delta E+ \Delta n. RT$

$=-6313+3.5\times 8.314\times 10^{-3} \times 3.596=-6312\,kJ/mol$

Therefore, $\Delta_{r}H$ of the reaction is -6312 kJ/mol.

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3 years ago

A pH -solution is more acidic than one with pH 6 by a factor of (a) 4000 (b) 2 (c) 10000 (d) 8000

jonny [76]

the correct option is c ) 10,000...
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3 years ago

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