<span>What
is the ph of an acetic acid solution if 10 drops are titrated with 70
drops of a 0.65 m koh solution? (ka for acetic acid = 1.8 x 10-5)?
[KOH] = 0.65 M
[OH] = 0.65 M
</span>Dilute your mom
<span>[OH]Dil= 0.65 M * 70/80 = 0.56875 M
pH = 5.4
</span>
Answer: true
Explanation: In this example, the processes (perceive, process, and respond), are done in a matter of milliseconds, but reaction time can vary depending on a variety of factors: Complexity of the stimulus-The more complex the stimulus, the more information that has to be processed, the longer this process will take.
Answer:
••It's melting point equals -38.8 degrees Celsius because it is mercury. |••
Explanation:
This one makes the most sense out of the answers.
Answer:
Coke.
Explanation:
The distillation of coal tar can obtain aromatic compounds like benzene and toluene, and also phenolic compounds like phenol. Hence, the only option here that cannot be obtained from the distillation of coal tar is coke.
Hope this helped!
Answer:
See explanation and picture below
Explanation:
First, in the case of methyloxirane (Also known as propilene oxide) the mechanism that is taking place there is something similar to a Sn2 mechanism. Although a Sn2 mechanism is a bimolecular substitution taking place in only step, the mechanism followed here is pretty similar after the first step.
In both cases, the H atom of the HBr goes to the oxygen in the molecule. You'll have a OH⁺ in both. However, in the case of methyloxirane the next step is a Sn2 mechanism step, the bromide ion will go to the less substitued carbon, because the methyl group is exerting a steric hindrance. Not a big one but it has a little effect there, that's why the bromide will rather go to the carbon with more hydrogens. and the final product is formed.
In the case of phenyloxirane, once the OH⁺ is formed, the next step is a Sn1 mechanism. In this case, the bond C - OH⁺ is opened on the side of the phenyl to stabilize the OH. This is because that carbon is more stable than the carbon with no phenyl. (A 3° carbon is more stable than a 2° carbon). Therefore, when this bond opens, the bromide will go there in the next step, and the final product is formed. See picture below for mechanism and products.