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Slav-nsk [51]
3 years ago
11

When HCl(g) reacts with NH3(g) to form NH4Cl(s) , 176 kJ of energy are evolved for each mole of HCl(g) that reacts. Write a bala

nced thermochemical equation for the reaction with an energy term in kJ as part of the equation.
Chemistry
1 answer:
Orlov [11]3 years ago
8 0

Answer:

q = -176kJ

Explanation:

HCl and NH3 reacts as following to NH4Cl

HCl(g) + NH3(g)=========>NH4Cl(s)   : ΔH = -176 KJ

Clearly,

ENERGY IS EVOLVED MEANING IT IS A EXOTHERMIC REACTION .

therefore, the value of heat evolved as q = -176kJ

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Answer:

Nuclear Fusion reactions power the Sun and other stars. In a fusion reaction, two light nuclei merge to form a single heavier nucleus.The process releases energy because the total mass of the resulting single nucleus is less than the mass of the two original nuclei

Explanation:

Nuclear fusion is a process in which atomic nuclei are fused together to form heavier nuclei. ... Like fission, nuclear fusion can also transmute one element into another. For example, hydrogen nuclei fuse in stars to form the element helium.

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Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical
melisa1 [442]

Answer:

-125.4

Explanation:

Target equation is 4C(s) + 5H2(g) = C4H10

These are the data equations for enthalpy of combustion

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  2. H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5
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To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...

Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.

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3 years ago
The half-life of radium-226 is 1590 years. if a sample contains 100 mg, how many mg will remain after 1000 years?
Katyanochek1 [597]

Answer:

a=64.7mg

Explanation:

Hello,

In this case, we need to remember that for the required time for a radioactive nuclide as radium-226 to decrease to one half its initial amount we are talking about its half-life. Furthermore, the amount of remaining radioactive material as a function of the half-lives is computed as follows:

a=a_0(\frac{1}{2} )^{\frac{t}{t_{1/2}} }

Therefore, for an initial amount of 100 mg with a half-life of 1590 years, after 1000 years, we have:

a=100mg(\frac{1}{2} )^{\frac{1000years}{1590years} }\\\\a=64.7mg

Best regards.

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