Aluminum carbide powder decomposes in water:

What is a dominant trait and a recessive trait

guajiro [1.7K]

Answer:

Dominant traits are always expressed when the connected allele is dominant, even if only one copy exists. Recessive traits are expressed only if both the connected alleles are recessive.

Explanation:

Freckles, cleft chin and dimples are all examples of a dominant trait.

5 0

2 years ago

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Hydrogenation reactions are used to add hydrogen across double bonds in hydrocarbons and other organic compounds. use average bo

Mamont248 [21]

H2(g) +C2H4(g)→C2H6(g)
H-H +H2C =CH2→H3C-Ch3
2C -H bonds and one C-C bond are formed while enthalpy change (dH) of the reaction,
H-H: 432kJ/mol
C=C: 614kJ/mol
C-C: 413 kJ/mol
C-C: 347 kJ/mol
dH is equal to sum of the energies released during the formation of new bonds or negative sign, and sum of energies required to break old bonds or positive sign.
The bond which breaks energy is positive.
432+614 =1046kJ/mol
Formation of bond energy is negative
2(413) + 347 = 1173 kJ/mol
dH reaction is -1173 + 1046 =-127kJ/mol

7 0

2 years ago

73.4 km to m then answer in correct number of significant numbers

Fittoniya [83]

Answer:

To determine the number of significant figures in a number use the following 3 rules:

To determine the number of significant figures in a number use the following 3 rules:Non-zero digits are always significant.

To determine the number of significant figures in a number use the following 3 rules:Non-zero digits are always significant.Any zeros between two significant digits are significant.

To determine the number of significant figures in a number use the following 3 rules:Non-zero digits are always significant.Any zeros between two significant digits are significant.A final zero or trailing zeros in the decimal portion ONLY are significant.

8 0

1 year ago

How many mL will a 0.205 mole sample of He occupy at 3.00 atm and 200 K? Report your answer to the nearest mL.

Tcecarenko [31]

1.1214 mL will a 0.205-mole sample of He occupy at 3.00 atm and 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Using equation PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 3.00 atm

V= ?

n=0.205 mole

R= $0.082057338 \;L \;atm \;K^{-1}mol^{-1}$