The electronic transition that will produce the lowest frequency is an electron falling from the 3rd to the 2nd energy level.
The question is incomplete, the complete question is;
As electrons fall from high energy orbitals to lower orbitals, energy is released in the form of electromagnetic radiation. The farther the electron falls, the more energy is released. Which of the following electronic transitions would produce a wave with the lowest frequency?
an electron falling from the 6th to the 2nd energy level
an electron falling from the 5th to the 2nd energy level
an electron falling from the 3rd to the 2nd energy level
an electron jumping from the 1st to the 2nd energy level
According to Bohr's theory, energy is absorbed or emitted when an electron moves from one energy level to another. This energy often occurs as visible light of known frequency and wavelength.
The magnitude of frequency of light depends on the difference in energy between the two energy levels. If the difference between the energy levels is high, the frequency of light is also high and vice versa.
The transition from 3rd to the 2nd energy level represents a low frequency transition because the energy levels are close together.
Learn more: brainly.com/question/10675485
Since this is Argon it would be a noble gas
(Na2Cr2O7) all the numbers are bellow not over
The mass numbers for two isotopes are unequal because they have different numbers of NEUTRONS.
Answer:
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