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yulyashka [42]
2 years ago
10

What is the slope of the line?

Chemistry
1 answer:
pychu [463]2 years ago
3 0

Answer:

The slope of the line is -\frac{10}{7}.

Explanation:

The slope of the line (m) is the change in dependent variable (y) divided by the change in independent variable (x):

m = \frac{y_{f}-y_{o}}{x_{f}-x_{o}} (1)

If we know that (x_{o}, y_{o}) = (0, 2) and (x_{f}, y_{f}) = (1.4, 0), then the slope of the line is:

m = \frac{0-2}{1.4-0}

m = -\frac{10}{7}

The slope of the line is -\frac{10}{7}.

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Answer:

Q = 1267720 J

Explanation:

  • Qt = QH2O + ΔHv

∴ QH2O = mCpΔT

∴ m H2O = 500 g

∴ Cp H2O = 4.186 J/g°C = 4.183 E-3 KJ/g°C

∴ ΔT = 120 - 50 = 70°C

⇒ QH2O = (500 g)(4.183 E-3 KJ/g°C)(70°C) = 146.51 KJ

∴ ΔHv H2O = 40.7 KJ/mol

moles H2O:

∴ mm H2O = 18.015 g/mol

⇒ moles H2O = (500 g)(mol/18.015 g) = 27.548 mol H2O

⇒ ΔHv H2O = (40.7 KJ/mol)(27.548 mol) = 1121.21 KJ

⇒ Qt = 146.51 KJ + 1121.21 KJ = 1267.72 KJ = 1267720 J

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