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2 years ago

What is the slope of the line?

Chemistry

1 answer:

pychu [463]2 years ago

3 0

Answer:

The slope of the line is $-\frac{10}{7}$ .

Explanation:

The slope of the line ( $m$ ) is the change in dependent variable ( $y$ ) divided by the change in independent variable ( $x$ ):

$m = \frac{y_{f}-y_{o}}{x_{f}-x_{o}}$ (1)

If we know that $(x_{o}, y_{o}) = (0, 2)$ and $(x_{f}, y_{f}) = (1.4, 0)$ , then the slope of the line is:

$m = \frac{0-2}{1.4-0}$

$m = -\frac{10}{7}$

The slope of the line is $-\frac{10}{7}$ .

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A nuclear reactor core must stay at or below 95 °C to remain in good working condition. Cool water at a temperature of 10 °C is

aliina [53]

Answer:

$\large \boxed{\text{67 000 g}}$

Explanation:

This is a problem in calorimetry — the measurement of the quantities of heat that flow from one object to another.

It is based on the Law of Conservation of Energy — Energy can be transformed from one type to another, but it cannot be destroyed or created.

If heat flows out of the reactor (negative), the same amount of heat must flow into the water (positive).

Since there is no change in total energy,

heat₁ + heat₂ = 0

The symbol for the quantity of heat transferred is q, so we can rewrite the word equation as

q₁ + q₂ = 0

The formula for the heat absorbed or released by an object is

q = mCΔT, where

m = the mass of the sample

C = the specific heat capacity of the sample, and

ΔT = T_f - T_i = the change in temperature

1. Equation

There are two heat flows in this problem,

heat released by reactor + heat absorbed by water = 0

q₁ + q₂ = 0

q₁ + m₂C₂ΔT₂ = 0

2. Data:

q₁ = -23 746 kJ

m₂ = ?; C₂ = 4.184 J°C⁻¹g⁻¹; T_f = 95 °C; T_i = 10 °C

3. Calculations

(a) Convert kilojoules to joules

$q_{1} = -\text{23 746 kJ} \times \dfrac{\text{1000 J}}{\text{1 kJ}} = -\text{23 746 000 J}$

(b) ΔT

ΔT₂ = T_f - T_i = 95 °C - 10 °C = 85 °C

(c) m₂

$\begin{array}{rcl}q_{1} + q_{2} & = & 0\\\text{-23 746 000 J} + m_{2} \times 4.184 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$} \times 85 \, ^{\circ}\text{C} & = & 0\\\text{-23 746 000 J} + 356m_{2} \text{J$\cdot$g}^{-1} & = & 0\\356m_{2} \text{g}^{-1} & = & 23746000\\m_2&=& \dfrac{23746000}{\text{356 g}^{-1}}\\\\ & = & \textbf{67000 g}\\\end{array}\\$

$\text{You must circulate $\large \boxed{\textbf{67 000 g}}$ of water each hour.}$

7 0

3 years ago

Pls help need it now as I don't know the answer

ioda

Answer:

Iron :)))))))))))))))))))))))))

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2 years ago

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What are the trends for atomic size and ionization? Explain why for each trend. Tell me the direction- up or down a group and ac

Alinara [238K]

Answer:

See explanation

Explanation:

Atomic size increases down the group due to the addition of more shells.

As more shells are added and repulsion of inner electrons become more significant, atomic size increases down the group. However, across the period, atomic size decreases due to increase in effective nuclear charge without any increase in the number of shells. This causes increased attraction between the nucleus and the outermost shell thereby decreasing the size of the atom.

Ionization energy decreases down the group because the outermost electron is more shielded by inner electrons making it easier for this outermost electron to be lost. Across the period, ionization energy increases due to increase in effective nuclear charge which makes it more difficult to remove the outermost electron due to increased nuclear attraction.

5 0

2 years ago

The electron transport process makes water and ATP and is sometimes called ________ because it requires oxygen. oxidation dephos

tatyana61 [14]

<span>The electron transport process makes water and ATP and is sometimes called Oxidative phosphorylation because it requires oxygen.</span>

4 0

3 years ago

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What is the value of R in the ideal gas law?

dybincka [34]

It’s option B 0.0821L.atm/mol.K

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2 years ago