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Hitman42 [59]
3 years ago
10

In a popular song from 1970, the musical group Crosby, Stills, and Nash use the line, "We are stardust." Why is this statement t

rue?
Chemistry
2 answers:
Morgarella [4.7K]3 years ago
7 0
<span>It is true because Earth was formed by a heart of a star, which is the same as stardust.
</span>
____ [38]3 years ago
6 0

Answer:

C

Explanation:

C) All elements, including those in our body, that are heavier than hydrogen are produced by fusion at the center of stars. Explosions of these stars then lead to the creation of planets and organisms.

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A community needs more electrical energy. The community is located in an
Paha777 [63]

Answer:

D BIOMASS ENERGY

Explanation:

Most biomass requires arable land to develop. This means

that land used for biofuel crops such as corn and soybeans

are unavailable to grow food or provide natural habitats.

Forested areas that have matured for decades (so-called

“old-growth forests”) are able to sequester more carbon

than newly planted areas.

7 0
2 years ago
Okay im clueless and over thinking this question can someone please help me out
Crank

A cookie made from flour, eggs, sugar, butter, and chocolate chips is an example of a heterogeneous mixture.

Also, mixing the sugar flavoring in water, since you're mixing two different states of matter.

6 0
3 years ago
Fatty acids that contain no carbon-carbon double bonds are referred to as.
ratelena [41]

Answer:

saturated fatty acids

7 0
2 years ago
2.50g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 12
Art [367]

Answer:

                      Molecular Formula  =  C₁₀H₈

Explanation:

Step 1: <u>Calculating Moles for each Element:</u>

C  =  Mass of CO₂ × (1 mol of CO₂÷ M.Mass of CO₂) × (1 mol of C ÷ 1 mol of CO₂)

C  =  8.60 g × (1 mol of CO₂÷ 44.011 g.mol⁻¹) × (1 mol of C ÷ 1 mol of CO₂)

C =  0.1954 mol

H  =  Mass of H₂O × (1 mol of H₂O ÷ M.Mass of H₂O) × (2 mol of H ÷ 1 mol of H₂O)

H  = 1.41 g × (1 mol of H₂O ÷ 18.106 g.mol⁻¹) × (2 mol of H ÷ 1 mol of H₂O)

H =  0.1557 mol

Step 2: <u>Calculate the Smallest whole number ratio as,</u>

                                 C                                                        H

                              0.1954                                               0.1557

                      0.1954/0.1557                                  0.1557/0.1557

                               1.25                                                       1

Multiply ratio by 4,

                                 5                                                         4

Result:

          Empirical Formula of Propane is C₅H₄

Step 3: <u>Calculate Molecular Formula:</u>

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                     n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  128.0 g.mol⁻¹

Empirical Formula Weight  =  5 (C) + 4 (H) =  64 g.mol⁻¹

So,

                     n  =  128.0 g.mol⁻¹ ÷ 64 g.mol⁻¹

                     n  =  2

Putting Empirical Formula and value of "n" in equation 1,

                    Molecular Formula  = 2 × C₅H₄

                    Molecular Formula  =  C₁₀H₈

4 0
3 years ago
A 0.1014 g sample of a purified compound containing C, H, and, O was burned in a combustion apparatus and produced 0.1486 g CO2
Alina [70]

Answer: The empirical formula for the given compound is CH_2O

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=0.1486g

Mass of H_2O=0.0609g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.1486 g of carbon dioxide, \frac{12}{44}\times 0.1486=0.0405g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.0609 g of water, \frac{2}{18}\times 0.0609=0.00677 of hydrogen will be contained.

Mass of oxygen in the compound = (0.1014) - (0.0405 + 0.00677) = 0.054 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.0405g}{12g/mole}=0.003375moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.00677g}{1g/mole}=0.00677moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.054g}{16g/mole}=0.003375moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.485 moles.

For Carbon = \frac{0.003375}{0.003375}=1

For Hydrogen  = \frac{0.00677}{0.003375}=2.00\times 2

For Oxygen  = \frac{0.003375}{0.003375}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 2 : 1

The empirical formula for the given compound is C_1H_2O_1=CH_2O

Thus, the empirical formula for the given compound is CH_2O

8 0
3 years ago
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