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Aleonysh [2.5K]
3 years ago
7

The universe is made up of ____

Chemistry
2 answers:
vladimir2022 [97]3 years ago
7 0
The correct should be A. thousands of galaxies
yKpoI14uk [10]3 years ago
5 0
A) thousands of Galaxies

Think, you have the Andromeda Galaxy, The Tobacco Galaxy, the Milky Way Galaxy and many many more
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Which process is characterized by the movement of particles?.
Serjik [45]

Answer: Diffusion is the movement of particles from a high to low particle concentration, while osmosis is the movement of water from a high to a low water concentration.

Explanation:

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3 years ago
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Write skeleton equations for the following reactions
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Al +3CuCl--->AlCl3+3Cu , its balanced equation
8 0
3 years ago
What is the osmotic pressure in atm of
Dmitrij [34]

Answer:

12.2329 atm

Explanation:

Applying

PV = nRT.................... Equation 1

Make P the subject of the equation

P = (n/V)RT................ Equation 2

Where P = Osmotic pressure, (n/V) = Molarity of urea, T = Temperature, R = molar gas constant.

From the question,

Given: (n/V) = 0.5 M, T = 25°C = (273+25) = 298 K, R = 0.0821 Latm/mol.K

Substitute these values into equation 2

P = (0.5)(298)(0.0821)

P = 12.2329 atm

5 0
3 years ago
150 words describing Bohr’s model, and the fundamental principles behind it. Also, explain how Bohr’s model is different from Ru
luda_lava [24]
Bohr's model is different from Rutherford's model by Bohr's model has 150 words , fundamental principles. also Rutherford's model does not have 150 words and fundamental principles. <span />
8 0
3 years ago
At a certain temperature, 0.3411 0.3411 mol of N 2 N2 and 1.661 1.661 mol of H 2 H2 are placed in a 2.50 2.50 L container. N 2 (
Sveta_85 [38]

<u>Answer:</u> The equilibrium constant for the above reaction is 1.31

<u>Explanation:</u>

We are given:

Initial moles of nitrogen gas = 0.3411 moles

Initial moles of hydrogen gas = 1.661 moles

Equilibrium moles of nitrogen gas = 0.2001 moles

For the given chemical reaction:

                   N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

<u>Initial:</u>         0.3411      1.661

<u>At eqllm:</u>     0.3411-x  1.661-3x      2x

Evaluating for 'x', we get:

\Rightarrow (0.3411-x)=0.2001\\\\\Rightarrow x=0.3411-0.2001=0.141

Volume of the container = 2.50 L

The expression of K_c for the above equation follows:

K_c=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}

We are given:

[NH_3]=\frac{2\times 0.141}{2.50}=0.1128M

[N_2]=\frac{0.2001}{2.5}=0.08004M

[H_2]=\frac{1.661-(3\times 0.141)}{2.5}=0.4952M

Putting values in above expression, we get:

K_c=\frac{(0.1128)^2}{0.08004\times (0.4952)^3}\\\\K_c=1.31

Hence, the equilibrium constant for the above reaction is 1.31

5 0
3 years ago
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