Question

(d) What is the mass percentage of water in CdCl2.4H2O?​

Answer 1

The mass percentage of water (H₂O) in cadmium chloride tetra hydratesolution is equal to the 28.2%.

How do we calculate mass percentage?

Mass percentage of any substabce present in any solution will be calculated as:
Mass percent = (Mass of substance/Total mass of solution)×100%

According to the question,

Mass of water (H₂O) = 18.02 g/mol

Mass of solvent (CdCl₂.4H₂O) = 183.32 + 4(18.02) = 255.4 g/mol

On putting values, we get

Mass percent = (18.02 / 255.4) × 100% = 28.2%

Hence mass percent of water is 28.2%.

To know more about mass percent, visit the below link:

brainly.com/question/13896694

Answer 2

Answer is 28.2%

Explanation:
Percent Composition by mass=Molar mass for part of compound/ Molar mass Whole compound x 100

18.02= H20 molar mass
183.32= cdCL2 Molar mass

4(18.02)=72.08 g/mol

183.32+72.08=255.4g/mol

72.08gm/255.4 g/mol x 100= 28.2%