1747.2 ml of HNO3 is required to reach methyl orange endpoint.
Explanation:
Number of moles of NaOH solution having 17.5 gram NaOH in 350ml of water.
Atomic weight of NaOH = 40 g/mol
thus number of moles= 17.5/40
= 0.437 moles
Now the molarity of the solution is calculated as
M=n/C
= 0.437/O.35 LITRES
= 1.248 M solution of the base
the molarity of acid is given as 0.25 M of HNO3
From the formula
M1V1=M2V2 we can calculate the volume of HNO3 required to make solution acidic.
1.248*350= 0.25*v2
v2= 1.248*350/0.25
= 1747.2 ml
Thus 1747.2 ml of HNO3 is required.
NOTHING really but as the stove is on with water boiling the air get moist
Answer:
Determine the approximate amount of potassium nitrate (NaNO3) that must be mixed with 150 g of water to obtain a saturated solution at 10ºC.
A) 80 g
B) 40 g
C) 120 g
D) 160 g
Answer:Heavy rainfall causes a landslide on the side of a mountain
Explanation: The hydrosphere is the water in the world. The geosphere is rocks and earth.
Answer:
41.54 grams of oxygen are required to burn 13.5 g of acetylene
Explanation:
The balanced reaction is:
2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- C₂H₂: 2 moles
- O₂: 5 moles
- CO₂: 4 moles
- H₂O: 2 moles
Being the molar mass of the compounds:
- C₂H₂: 26 g/mole
- O₂: 32 g/mole
- CO₂: 44 g/mole
- H₂O: 18 g/mole
By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- C₂H₂: 2 moles* 26 g/mole= 52 grams
- O₂: 5 moles* 32 g/mole= 160 grams
- CO₂: 4 moles* 44 g/mole= 176 grams
- H₂O: 2 moles* 18 g/mole= 36 grams
You can apply the following rule of three: if by stoichiometry 52 grams of acetylene react with 160 grams of oxygen, 13.5 grams of acetylene react with how much mass of oxygen?

mass of oxygen= 41.54 grams
<u><em>41.54 grams of oxygen are required to burn 13.5 g of acetylene</em></u>
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