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____ [38]
2 years ago
8

A small dog eats 3/4 of a cup of dog food twice a day. Using d for the numbers of days and f for the amount of food write an equ

ation relating variables
Mathematics
1 answer:
rosijanka [135]2 years ago
6 0

Answer:

f = food variable

d = number of days

Equation: f = 1.5d

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4 years ago
Please help…
tino4ka555 [31]

10

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−

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9

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The rational numbers are:

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−

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7 0
3 years ago
Calculus help ASAP!!!
anastassius [24]
Let c\in(0,\infty). Then the definite integral can be split up at t=c so that

\displaystyle F(x)=\int_{t=2x}^{t=5x}\frac{\mathrm dt}t
\displaystyle=\int_{t=2x}^{t=c}\frac{\mathrm dt}t+\int_{t=c}^{t=5x}\frac{\mathrm dt}t
\displaystyle=-\int_{t=c}^{t=2x}\frac{\mathrm dt}t+\int_{t=c}^{t=5x}\frac{\mathrm dt}t

Now take the derivative. By the fundamental theorem of calculus, you have

\displaystyle\frac{\mathrm dF}{\mathrm dx}=\frac{\mathrm d}{\mathrm dx}\left[\int_{t=c}^{t=5x}\frac{\mathrm dt}t-\int_{t=c}^{t=2x}\frac{\mathrm dt}t\right]
=\displaystyle\frac1{5x}\dfrac{\mathrm d}{\mathrm dx}[5x]-\frac1{2x}\dfrac{\mathrm d}{\mathrm dx}[2x]
=\dfrac5{5x}-\dfrac2{2x}
=\dfrac1x-\dfrac1x
=0

Then integrating with respect to x, we recover F(x) and find that

\displaystyle\int\dfrac{\mathrm dF}{\mathrm dx}\,\mathrm dx=\int0\,\mathrm dx
F(x)=C

where C is an arbitrary constant.
7 0
3 years ago
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