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Artemon [7]
2 years ago
7

Write 8 38 in lowest terms.

Mathematics
1 answer:
belka [17]2 years ago
3 0

Answer:

4/19

Step-by-step explanation:

Both the numerator and denominator can be divided by 2, giving 4/19

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Mr. Rahman gave 40% of the money he had to his wife. he also gave 20% of the remaining amount to each of his 3 sons. half of the
makkiz [27]

Answer:

53760

Step-by-step explanation:

12000 x 2 = 24000

24000 x .20 = 4800 this is the amount he gave to each of his sons

4800 x 3 = 14400 this is the amount he gave to his sons in total

24000 + 14400 = 38400

38400 x .40 = 15360 this is how much he gave to his wife

15360 + 38400 = 53760

7 0
3 years ago
Write each number as a product using the GCF as a​ factor, and apply the Distributive Property.
Rasek [7]

The distributive property: a(b + c) = ab + ac.

Factors of 38: 1, 2, 19, 38

Factors of 57: 1, 3, 19, 57

GCF(38, 57) = 19

38 + 57 = 19 · 2 + 19 · 3 = 19(2 + 3)

6 0
3 years ago
50 POINTS!!!! NEED HELP!!! 2 QUESTIONS!!!! please answer correctly. i begging u
frosja888 [35]
Dawson's annual premium will be $2,462.40. This can be found by going across from "Male 40-44" over to "20-year coverage" which is $13.68. Since $13.68 is per $1000 of coverage, you would multiply it by 180 to get $2,462.40.

Rachel's checks I believe would have a deduction of $63.14.
4 0
3 years ago
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A small regional carrier accepted 23 reservations for a particular flight with 20 seats. 14 reservations went to regular custome
MrRissso [65]

Answer:

- The probability that overbooking occurs means that all 8 non-regular customers arrived for the flight. Each of them has a 56% probability of arriving and they arrive independently so we get that  

P(8 arrive) = (0.56)^8 = 0.00967

- Let's do part c before part b. For this, we want an exact booking, which means that exactly 7 of the 8 non-regular customers arrive for the flight. Suppose we align these 8 people in a row. Take the scenario that the 1st person didn't arrive and the remaining 7 did. That odds of that happening would be (1-.56)*(.56)^7.

Now take the scenario that the second person didn't arrive and the remaining 7 did. The odds would be  

(0.56)(1-0.56)(0.56)^6 = (1-.56)*(.56)^7. You can run through every scenario that way and see that each time the odds are the same. There are a total of 8 different scenarios since we can choose 1 person (the non-arriver) from 8 people in eight different ways (combination).  

So the overall probability of an exact booking would be [(1-.56)*(.56)^7] * 8 = 0.06079

- The probability that the flight has one or more empty seats is the same as the probability that the flight is NOT exactly booked NOR is it overbooked. Formally,  

P(at least 1 empty seat) = 1 - P(-1 or 0 empty seats)  

= 1 - P(overbooked) - P(exactly booked)

= 1 - 0.00967 - 0.06079  

= 0.9295.

Note that, the chance of being both overbooked and exactly booked is zero, so we don't have to worry about that.

Hope that helps!

Have a great day :P

7 0
3 years ago
In one day's work at the nursery, sale and mary together potted 74 plants. If dale planted 48 of those plants how many did mary
xenn [34]

Answer:

Mary potted 26 of the plants.

Step-by-step explanation:

74 - 48 = 26

7 0
3 years ago
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