The sum of three numbers is 13. The sum of twice the first number, 5 times the second number, and 6 times the third number is 67
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Answer:
<h2>Solution,
Let the points be A and B
A(-4 , 1)------>( X1, y1)
B(2,4)---------->( x2, y2)
Now,
Gradient:
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The equation has one extraneous solution which is n ≈ 2.38450287.
Given that,
The equation;
We have to find,
How many extraneous solutions does the equation?
According to the question,
An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.
To solve the equation cross multiplication process is applied following all the steps given below.
The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y
with 0 and solve for x. The graph of the equation is attached.
n ≈ 2.38450287
Hence, The equation has one extraneous solution which is n ≈ 2.38450287
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