So if v^y = 1/(5 root V), then v^y = 1/(V^(1/5)) just like how X^(1/2) = 2 root X or more commonly known as the square root. So if v^y = 1/(V^(1/5)), then v^y = V^(-1/5) because X^(-1) = 1/X Thus you get y = -1/5 because V^y = V^(-1/5) Hope this helps!
