2 years ago

HELP ME

Mathematics

1 answer:

Leviafan [203]2 years ago

5 0

Answer:Mean is greater than the median and the range is 6

Step-by-step explanation: Mean is the average 5+6+7+11+11/5 = 8

Mode is the number occurring most 11

Median is the middle number 7

Range is the highest -lowest 11-5=6

You might be interested in

Please show your work and help

Levart [38]

Answer:

22.5 cm

Step-by-step explanation:

An equilateral triangle has 3 equal sides

perimeter is the sum of all 3 sides, hence

perimeter = 3 × 7.5 = 22.5 cm

8 0

3 years ago

Quick Question! Please help!

8090 [49]

Answer:

C --- b^16

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Geneva rode her bike a total of 2 1/2 miles from her house to school. First she rode 4/5 mile from her house to the park. Then s

Sonja [21]

Add 4/5 and 1/5 to make 5/5 or 1 mile the subtract 1 from 2 1/2 to equal 1 1/2 miles

8 0

3 years ago

For f(x) = x3-x2, which gives an output of 48?<br> A. f(-8)<br> B. f(-4)<br> C. f(4)<br> D. f(8)

Butoxors [25]

Answer:

The input is x−2, therefore

Step-by-step explanation:

f(x−2)=(x−2)2−3(x−2)+1

7 0

2 years ago

A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one

d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

$P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855$

The probability that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0

3 years ago