When might a therapist be required to violate confidentiality?
1 answer:
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42) The sailboat travels east with velocity 
, while the current moves south with speed 
. Since the two velocities are perpendicular to each other, he resultant velocity will be given by the Pytagorean theorem:
and the direction is in between the two original directions, therefore south-east. So, the correct answer is
D) 42 mph southeast
43) Since the light moves by uniform motion, we can calculate the distance corresponding to one light year by using the basic relationship between velocity, space and time. In fact, we know the velocity:
and the time is one year, corresponding to:
therefore, the distance corresponding to one light year is:
Therefore, the correct answer is D.
44) For the purpose of the problem, we can assume that the light travels instantaneously from the flash to us (because the distances involved are very small), so the time between the flash and the thunder corresponds to the time it took for the sound to travel to us.
The speed of sound is
And since the time between the flash and the thunder is t=3 s, the distance is
Therefore, the correct answer is A) 3/5 mile.
and the direction is in between the two original directions, therefore south-east. So, the correct answer is
D) 42 mph southeast
43) Since the light moves by uniform motion, we can calculate the distance corresponding to one light year by using the basic relationship between velocity, space and time. In fact, we know the velocity:
and the time is one year, corresponding to:
therefore, the distance corresponding to one light year is:
Therefore, the correct answer is D.
44) For the purpose of the problem, we can assume that the light travels instantaneously from the flash to us (because the distances involved are very small), so the time between the flash and the thunder corresponds to the time it took for the sound to travel to us.
The speed of sound is
And since the time between the flash and the thunder is t=3 s, the distance is
Therefore, the correct answer is A) 3/5 mile.
To answer this question, we will refer to the attached diagram which represents the complete rock cycle.
Rock 1:
Formed when rock 2 and rock 3 were subjected to intense heat and pressure inside the earth.
Referring to the diagram, we will find that heat and pressure are the factors required to form metamorphic rocks
Therefore, rock 1 is metamorphic
Rock 2:
Formed when rock 1 and rock 3 were broken down into mineral (sediments) which accumulate and are subjected to pressure.
Referring to the diagram, we will find that this description would lead to the formation of sedimentary rocks.
Therefore, rock 2 is a sedimentary rock.
Rock 3:
Formed when rock 1 and rock 2 were buried inside the earth and melted because of heat and magma.
Referring to the diagram, we would find that melting then cooling of magma would lead to formation of igneous rock.
Therefore, rock 3 is igneous rock.
Based on the above, the correct choice would be:
Rock 1: Metamorphic
Rock 2: Sedimentary
Rock 3: Igneous
Rock 1:
Formed when rock 2 and rock 3 were subjected to intense heat and pressure inside the earth.
Referring to the diagram, we will find that heat and pressure are the factors required to form metamorphic rocks
Therefore, rock 1 is metamorphic
Rock 2:
Formed when rock 1 and rock 3 were broken down into mineral (sediments) which accumulate and are subjected to pressure.
Referring to the diagram, we will find that this description would lead to the formation of sedimentary rocks.
Therefore, rock 2 is a sedimentary rock.
Rock 3:
Formed when rock 1 and rock 2 were buried inside the earth and melted because of heat and magma.
Referring to the diagram, we would find that melting then cooling of magma would lead to formation of igneous rock.
Therefore, rock 3 is igneous rock.
Based on the above, the correct choice would be:
Rock 1: Metamorphic
Rock 2: Sedimentary
Rock 3: Igneous
Answer:
Explanation:
Given that,
Diffraction grating is ruled by 900 lines/cm
The detector length is
h= 1.2cm =1.2/100= 0.012m
Short wavelength is λs= 564.6nm
Long wavelength is λl = 571.2nm
Question: how far from the grating should the screen with the detector on it be placed. x=?
Since there are 900 lines per centimeter, each line is separated by 1/900 of a centimeter.
The distance between slits is d is given as
d = 1/900 cm
d = 0.00111cm
d = 0.0000111m = 1.11×10^-5 m
Let us call the two angles θs for short-wavelength (564.6nm) and θl for long-wavelength (571.2nm). Diffraction grating is given as
d sin(θs)= mλl
sin(θs)= mλl / d
Since we are given 7th order, then m=7
sin(θs)= 7×564.6×10^-9 / 1.11×10^-5
sin(θs)= 0.3557
θs = arcsin(0.3557)
θs = 20.84°
Applying the same principle for long wavelength
d sin(θl)= mλl
sin(θl)= mλl / d
Since we are given 7th order, then m=7
sin(θl)= 7×571.2×10^-9 / 1.11×10^-5
sin(θl)= 0.3599
θl = arcsin(0.3599)
θl = 21.1°
Using trigonometry,
Then, tanθ = opposite/adjacent
Adjacent is the distance between the screen and the detector
Opposite Is the length of detector, which serves like a height
Tanθl = h/x
x= h / Tan(θl)
x = 0.012 / Tan(21.1)
x = 0.0311m
x =3.11cm
Check attachment for better understanding the how I used the trigonometric function and the triangle I used.
