Answer:
angular frequency is 209439.51 rad/sec
maximum displacement is 0.010504 m
Explanation:
Given data
mass = 2.3 × 10^-20 kg
period = 3.0 × 10^-5 s
maximum speed = 2.2 × 10^3 m/s
to find out
the angular frequency and maximum displacement
solution
we know angular frequency formula that is
angular frequency = 2 π / period
put here period value we get angular frequency
angular frequency = 2 π / 3.0 × 10^-5
angular frequency is 209439.51 rad/sec
maximum displacement formula is
speed = angular frequency × maximum displacement
put all value and we get maximum displacement
maximum displacement = 2.2 × 10^3 / 209439.51
maximum displacement is 0.010504 m
The answer for this question is neon
Complete Question:
In the same configuration of the previous problem 3, four long straight wires are perpendicular to the page, and their cross sections form a square of edge length a = 13.5 cm. Each wire carries 7.50 A, and the currents are out of the page in wires 1 and 4 and into the page in wires 2 and 3.
a) Draw a diagram in a (x,y) plane of the four wires with wire 4 perpendicular to the origin. Indicate the current's directions.
b) Draw a diagram of all magnetic fields produced at the position of wire 3 by the other three currents.
c) Draw a diagram of all magnetic forces produced at the position of wire 3 by the other three currents.
d) What are magnitude and direction of the net magnetic force per meter of wire length on wire 3?
Answer:
force, 1.318 ₓ 10⁻⁴
direction, 18.435°
Explanation:
The attached file gives a breakdown step by step solution to the questions
Weight = mass * gravity = 60 kg * 3.75 m/s² = 225 N
<span>Option D.</span>