Step-by-step explanation:
∆PQR similar to ∆ JKL
JK/KL= PQ/QR
6/12=3/QR
QR=3×2= 6
therefore, tan(R) = PQ/QR = 3/6=1/2
and, tan(J) = KL/JK =12/6=2


tan(J)=4.tan(R)
option D
Answer:
line two is probably he line of best fit.
2
Mark brainliest please
Hope this helps
Hello!
∠GCE = 14° (corresponding angles)
∠GEC = 180° - 78° - 14° (sum of angles in a triangle)
∠GEC = 88°
4x + 88° = 180°
4x = 180° - 88°
4x = 92°
x = 23°