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meriva
2 years ago
11

Can you graph this equation - Y=3×^2

Mathematics
2 answers:
Vladimir [108]2 years ago
8 0
So you start at 0 then (1,3) , (2,12) and the other side would be (-1,3) , (-2,12)
lesya692 [45]2 years ago
7 0
Fill in the x values with easy numbers like -1, -2, 0, 1, 2.
After there figure out the y values.
Ex Y= (3*0)^2    ×=0, y=0
E×  Y=(3*-1)^2   x= -1, y= 9

I think you can do the rest.  If you are using division, use numbers that are divisible by the other number to make it easy.
Always use low numbers if possible, so you can graph.
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There are 420 students. 63 students were out sick. What percent of the student population is ill?
emmainna [20.7K]
To find the percentage,here's what we can do:
\frac{student \: out \: sick}{original \: population} \times 100\%

The percentage would then be:
=63/420×100%
=3/20×100%
=0.15×100%
=15%

Therefore the answer is 15%.

Hope it helps!
3 0
3 years ago
Read 2 more answers
12 is what percent of 19​
VikaD [51]

Answer:

63%

Step-by-step explanation:

12/19=0.63157895

0.63157895*100=63.1578947

7 0
3 years ago
X = (y + 3) / 12 solve for y
slega [8]

Answer:

y = 12x-3

Step-by-step explanation:

X = (y + 3) / 12

Multiply each side by 12 to clear the fraction

12 x = (y+3)/12 *12

12x = y+3

Subtract 3 from each side

12x -3 = y+3-3

12x-3 =y

8 0
3 years ago
What’s the radius of this button ?
Neporo4naja [7]

Answer:

2.5 cm

Step-by-step explanation:

We see the diameter is 5cm

so the radius is half the diameter

5/2 = 2.5 cm

3 0
3 years ago
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2x² - 5x+1 has roots alpha and beta. Find alpha⁴+beta⁴ without solving the equation.
shepuryov [24]

Answer:

Step-by-step explanation:

\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\

= \dfrac{625}{16}- \dfrac{168}{16}-\dfrac{24}{16}\\\\\\= \dfrac{433}{16}

7 0
2 years ago
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