Answer:
Part A)
Part B) Length: 17.5 feet and Width: 14 feet
Step-by-step explanation:
Part A) Create an equation to represent the area of the basketball section A, in terms of the width W.
Let
L ----> the length of the rectangular basketball section
W ---> the width of the rectangular basketball section
we know that
The area of the rectangular basketball section is equal to
----> equation A
The length of the section will be 1.25 times the width of the section
so
----> equation B
substitute equation B in equation A
Part B) Jackson decides to make the area of the basketball section 245 square feet. What are the dimensions, in feet, of the basketball section?
we have
so
solve for W
Find the value of L
substitute the value of W in the equation B
therefore
The dimensions are :
Length: 17.5 feet
Width: 14 feet
