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ozzi
3 years ago
11

Yeah can someone help me plz

Mathematics
1 answer:
erastovalidia [21]3 years ago
3 0
11. you do 3x3=9 then plus 9+2 = 12 then 12 x 12 = 144
sorry idk 10.
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AB = 44 + 3xBC = 33 + yCD = 64 − xAD = 48 − 2yQuadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruen
Otrada [13]

The lengths (in centimeters) of the opposite side pairs are 59 cm , 38 cm. Option C) is the correct answer.

<u>Step-by-step explanation</u>:

<u>step 1</u> :

Given that,

Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent.

<u>step 2</u> :

The opposite sides are AB and CD respectively.

The another opposite sides are BC and AD respectively.

<u>step 3</u> :

If both pairs of opposite sides are congruent, then

AB = CD

44+3x = 64-x

3x+x = 64-44

4x = 20

x = 5

<u>step 4</u> :

BC = AD

33+y = 48-2y

y+2y = 48-33

3y = 15

y = 5

<u>step 5</u> :

Subsitute x=5 and y=5 in any of the given sides,

CD = 64-x = 64-5 = 59

∴ CD = 59 cm

BC = 33+y = 33+5 = 38

∴ BC = 38 cm

The lengths of the opposite side pairs are 59 cm , 38 cm.

3 0
3 years ago
Find the area of a circular pond having radius<br>Ans: 616 m<br>14 m.​
krek1111 [17]

Step-by-step explanation:

Area of circular pond=22/7×14×14

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>2</em><em>2</em><em>/</em><em>7</em><em>×</em><em>1</em><em>9</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>6</em><em>1</em><em>6</em><em>m</em>

3 0
2 years ago
n 2000 the population of a small village was 2,400. With an annual growth rate of approximately 1.68%, compounded continuously,
Nitella [24]

Answer:

The population would be 3358

Step-by-step explanation:

Since, exponential growth function if the growth is compound continuously,

A = Pe^{rt}

Where,

P = initial population,

r = growth rate per period,

t = number of periods,

Given,

The population in 2000, P = 2,400,

Growth rate per year = 1.68% = 0.0168,

Number of years from 2000 to 2020, t = 20,

Thus, the population in 2020,

A=2400 e^{0.0168\times 20}

=2400 e^{0.336}

= 3358.4136

\approx 3358

6 0
3 years ago
It's from the chapter : "exponents and powers"<br>i need the workings too<br>please help​
labwork [276]

Answer:

505/19

Step-by-step explanation:

Easy

so [3^3-(1/2)^(-3)*(1/19)]

simplify

3^3-8/19

3^3=27

27-8/19

convert element to fraction

(27*19)/19-8/19

combine

(27*19-8)/19

505/19

Have a wonderful day ask me if you have more questions about MATH that goes for anyone who needs math help

5 0
3 years ago
Assume that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles
OverLord2011 [107]

Answer:

Final answer is approx 6.644 years.

Step-by-step explanation:

Given that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles is 16% every year and that of cars is 25% every year.

So we can use growth formula:

A=P\left(1+r\right)^t

Then we get equation for motorcycles and cars as:

A=5.75\left(1+0.16\right)^t

A=3.5\left(1+0.25\right)^t

Now we need to find about when the sale of cars will be more than the sale of motorcycles. So we get:

3.5\left(1+0.25\right)^t>5.75\left(1+0.16\right)^t

3.5\left(1.25\right)^t>5.75\left(1.16\right)^t

3.5\left(1.25\right)^t>5.75\left(1.16\right)^t

\frac{\left(1.25\right)^t}{\left(1.16\right)^t}>\frac{5.75}{3.5}

\left(\frac{1.25}{1.16}\right)^t>1.64285714286

t\cdot\ln\left(\frac{1.25}{1.16}\right)>\ln\left(1.64285714286\right)

t>\frac{\ln\left(1.64285714286\right)}{\ln\left(\frac{1.25}{1.16}\right)}

t>6.6436473051

Hence final answer is approx 6.644 years.

7 0
3 years ago
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