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2 years ago

A _____________ is a line that provides an approximation of the relationship between the variables.

Mathematics

1 answer:

Furkat [3]2 years ago

8 0

Answer:

srat

Step-by-step explanation:hehe i really dont know

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Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to

denpristay [2]

Answer: The point estimate for the mean is <u>2.59</u> and the margin of error is <u>0.13</u> .

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\mu\pm E$ , where E is the margin of error .

Given : At the end of one year, the store used the weekly sales information to construct a 95% confidence interval for the mean number of emeralds sold per week.

The confidence interval they calculated was (2.46,2.72) .

The lower limit of the confidence interval : $\mu-E=2.46$ (1)

The upper limit of the interval : $\mu+E=2.72$ (2)

Adding (1) and (2) , we get

$2\mu=5.18\\\\\Rightarrow\mu=2.59$

Now, Subtracting (1) from (2) , we get

$2E =0.26\\\\\Rightarrow\ E=0.13$

Hence, the point estimate for the mean is 2.59 and the margin of error is 0.13 .

7 0

3 years ago

What is the mean of 9,5

larisa86 [58]

Answer:

Step-by-step explanation:

$mean = \frac{9 + 5}{2} = \frac{14}{2} = 7 \\$

7 0

2 years ago

If a square has the perimeter of 15.2 centimeters, what are 2 equations that can determine the perimeter of the square?

astraxan [27]

Answer:

1) $P=4s$

2) $P=4\sqrt{A}$

see the explanation

Step-by-step explanation:

we know that

The perimeter of the square is equal to

$P=4s$

where

s is the length side of the square

we have

$P=15,2\ cm$

substitute

$15.2=4s$

solve for s

$s=15.2/4=3.8\ cm$

The area of a square is equal to

$A=s^2$

substitute

$A=3.8^2=14.44\ cm^2$

we have that

$s=\sqrt{A}$

therefore

2 equations that can determine the perimeter of the square are

1) $P=4s$ ----> $P=4(3.8)=15.2\ cm$

2) $P=4\sqrt{A}$ ----> $P=4\sqrt{14.44}=15.2\ cm$

4 0

3 years ago

Using Accuracy and Precision

Fudgin [204]

Answer:

a little bit confusing

5 0

3 years ago

How do I write a recursive formula for this sequence? 2, 6, 18, 54, 162, ... I already know the common difference is x3.

dmitriy555 [2]

For the sequence 2, 6, 18, 54, ..., the explicit formula is: an = a1 ! rn"1 = 2 ! 3n"1 , and the recursive formula is: a1 = 2, an+1 = an ! 3 . In each case, successively replacing n by 1, 2, 3, ... will yield the terms of the sequence. See the examples below.

4 0

3 years ago