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natta225 [31]
3 years ago
5

What is the combined perimeter of these two rectangles?

Mathematics
2 answers:
GarryVolchara [31]3 years ago
5 0

Answer:

D) 24x + 52

Step-by-step explanation:

The perimeter of the purple rectangle is

P =2(l+w)

   =2 (4x+5  + 2x+7)

Combine like terms

   =2 (6x+12)

Distribute

  = 12x +24

The perimeter of the white rectangle is

P =2(l+w)

P =2(3x+14 +3x)

Combine like terms

  =2(6x+14)

Distribute

 12x +28

Add the perimeters

12x +24 +  12x +28

24x +52

Simora [160]3 years ago
3 0
<h3><u><em>Answer:</em></u></h3><h3><u><em>The Answer is D) 24x + 52</em></u></h3><h3><u><em>Step-by-step explanation:</em></u></h3><h3><u><em>Find the perimeter of each rectangle and then add them together. The perimeter of the first rectangle is 12x + 24 and the perimeter of the second rectangle is 12x + 28. The combined perimeter is 24x + 52</em></u></h3>
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5 (7) - 3 (-8)

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3 years ago
Sin(xy)-x=0 find dy/Dx
MariettaO [177]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2989024

——————————

You have  y  as an implicit function of  x:

sin(xy) – x = 0


Use implicit differentiation. As  y  is a function of  x, then you must apply the chain rule there:

  d                                 d
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 dx                               dx


  d                           d               d
—— [ sin(xy) ]  –  —— (x)  =  —— (0)
 dx                         dx             dx

  d
—— [ sin(xy) ]  –  1  =  0
 dx

  d
—— [ sin(xy) ]  =  1
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cos(xy)  ·  —— (xy) = 1
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Now, apply the product rule for that last derivative:

\mathsf{cos(xy)\cdot \left[\dfrac{d}{dx}(x)\cdot y+x\cdot \dfrac{dy}{dx}\right]=1}\\\\\\&#10;\mathsf{cos(xy)\cdot \left[1\cdot y+x\cdot \dfrac{dy}{dx}\right]=1}\\\\\\&#10;\mathsf{y\,cos(xy)+x\,cos(xy)\cdot \dfrac{dy}{dx}=1}


              dy
Isolate  —— :
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                   dy
x cos(xy) · ——  =  1 – y cos(xy)
                   dx


Assuming  x cos(xy) ≠ 0,

 dy          1 – y cos(xy)
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 dx            x cos (xy)


I hope this helps. =)

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