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3 years ago

What are star system

Physics

1 answer:

kolbaska11 [484]3 years ago

3 0

A number of stars that orbit each other bound by gravitational attraction.

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A car traveled 330 miles in 6 hours. What is the average speed?

shusha [124]

it is 55 mph that is ok

6 0

3 years ago

A small metal bead, labeled A, has a charge of 28 nC .It is touched to metal bead B, initially neutral, so that the two beads sh

Dmitry_Shevchenko [17]

Answer:

Explanation:

Let the charge on bead A be q nC and the charge on bead B be 28nC - qnC

Force F between them

4.8\times10^{-4} = $\frac{9\times10^9\times q\times(28-q)\times10^{-18}}{(5\times10^{-2})^2}$

=120 x 10⁻⁸ = 9 x q(28 - q ) x 10⁻⁹

133.33 = 28q - q²

q²- 28q +133.33 = 0

It is a quadratic equation , which has two solution

q_A = 21.91 x 10⁻⁹C or q_B = 6.09 x 10⁻⁹ C

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3 years ago

What hapens when someone has split brain

Slav-nsk [51]

Answer:

The procedure involves severing the corpus callosum, the main bond between the brain's left and right hemispheres. ... This impairment can result in split-brain syndrome, a condition where the separation of the hemispheres affects behavior and agency.

Explanation:

4 0

3 years ago

Two point charges q and 4q are at x=0 and x=l, respectively, and free to move. a third charge is placed so that the entire three

tatuchka [14]

Explanation :

It is given that, q and 4q are placed at a distance of l.

Let x is the distance where third charge is placed so that the entire three charge system is in static equilibrium.

Equilibrium means the net force acting on the system of charges is equal to zero. Let Q is the third charge.

So, $\dfrac{kqQ}{x^2}=\dfrac{k(Q)(4q)}{(l-x)^2}$

On solving,

$x=\dfrac{l}{3}$

For magnitude :

$\dfrac{kqQ}{(l/3)^2}=\dfrac{kq4q}{l^2}$

using $x=\dfrac{l}{3}$

$Q=\dfrac{4q}{9}$

So, a charge of -4q/9 is at a distance of l/3 is placed. It is placed to the right of +q.

8 0

4 years ago

A ball is thrown vertically upward from a height of 6 feet with an initial velocity of 41 feet per second. how high will the bal

maksim [4K]

Given: Height h = 6 ft or the vertical component "y" this become the initial height, therefore if you want to know the total height of the stone with respect to the ground. you can just add up the two value below.

Initial Velocity Vi = 41 ft/s g = -32.2 ft/s² acting downward

Require: Height h = ?

Formula: y = Vf² - Vi²/2g

y = 0 - (41 ft/s)²/2(-32.2 ft/s²)

y = -1,681 ft²/s²/(-64.4 ft/s²)

y = 26.10 ft

8 0

3 years ago