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vesna_86 [32]
3 years ago
15

The same strength force was exerted in the same direction on both Object A and Object B. Why did Object A go faster than Object

B?
Physics
1 answer:
VashaNatasha [74]3 years ago
6 0

Answer:

m_B > m_A

the mass of body B must be greater than the mass of body A

Explanation:

Newton's second law establishes a linear relationship between the force, the mass of the body and its acceleration

        F = m a

        a = F / m

Let's analyze this expression tells us that the force is of equal magnitude for the two bodies, but body A goes faster than body B, this implies that it has more relationships

         a_A > a_B

         \frac{F}{m_A} > \frac{F}{m_B}

         m_B > m_A

Therefore, for this to happen, the mass of body B must be greater than the mass of body A

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If an object falls for 4 seconds, how fast is it going when it hits the ground?
MArishka [77]

Acceleration due to gravity is about 9.8 m/s²

So after every second, the speed increase by 9.8 m/s

After 1 second, the object would fall at a speed of 9.8 m/s

After 2 seconds the object would fall at a speed of 19.6 m/s

So after 4 seconds, the object is going to be at a speed of:

9.8 x 4 = 39.2 m/s

-------------------------------------------------

<u>Answer</u>

39.2 m/s

3 0
4 years ago
Which of the following is NOT an example of an extensive physical property?
Step2247 [10]
D. density is your answer because density is an intensive property. By the way is this for FLVS?
7 0
3 years ago
Read 2 more answers
The friction force between a bag and the floor is 4 N. what is the net force acting on the bag? What is the acceleration of the
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Well, if the bag is moving across the floor at a constant velocity. Then I would assume that the Fnet force is equal to 0, and thus the value of acceleration would also be equal to 0.
6 0
3 years ago
You have recently been called to troubleshoot network connectivity problems at a user's workstation. You have found that the net
vekshin1

Answer:

C

Explanation:

Prevents further damage to the network cable.

8 0
3 years ago
If a rock is thrown upward on the planet Mars with a velocity of 18 m/s, its height (in meters) after t seconds is given by H =
lukranit [14]

Answer:

a) The velocity of the rock after 1 s is 14.28 m/s.

b) The velocity of the rock after "a" seconds is  18 m/s - 3.72 m/s² · a

c) The rock will hit the ground after 9.7 s.

d) The velocity with which the rock hits the surface is -18.1 m/s

Explanation:

Hi there!

Let´s write the equation:

H(t) = 18 m/s · t - 1.86 m/s² · t²

The velocity is the variaiton of the height over time, in other words, it is the derivative of the height function with respect to time. Then:

v(t) = dH/dt = 18 m/s - 2 · 1.86 m/s² · t

v(t) = 18 m/s - 3.72 m/s² · t

a) When t = 1 s:

v(1 s) = 18  m/s - 3.72 m/s² · 1 s

v(1 s) = 14.28 m/s

b) When t = a:

v(a) = 18 m/s - 3.72 m/s² · a

c) When the rock hits the surface, the height of the rock is 0:

H(t) = 18 m/s · t - 1.86 m/s² · t²

0 = 18 m/s · t - 1.86 m/s² · t²

0 = t(18 m/s - 1.86 m/s² · t)

t = 0

and

18 m/s - 1.86 m/s² · t = 0

t = -18 m/s /- 1.86 m/s²

t = 9.7 s

d) Let´s use the equation of velocity to find the velocity at t =  9.7 s when the rock hits the ground.

v(t) = 18 m/s - 3.72 m/s² · t

v(9.7 s) = 18 m/s - 3.72 m/s² · 9.7 s

v(9.7 s) = -18.1 m/s  

4 0
3 years ago
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