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Novosadov [1.4K]
2 years ago
15

How many electrons are unpaired in the orbitals of carbon?

Chemistry
1 answer:
igor_vitrenko [27]2 years ago
3 0

Answer:

2 unpaired electrons

Explanation:

Carbon's bonding state electron configuration is 1s2 2s1 2s1 2p1 2p1. So, there are 4 unpaired electrons in the orbitals of carbon in bonding state.

hope this helps

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almond37 [142]

Answer:

10.5 k.J.

Explanation:

7 0
2 years ago
After 11.5 days, 12.5% of a sample of radon-222 that originally weighed 42g remains. What is the half-life of this isotope?
Bond [772]
Half-life is defined as the amount of time it takes a given quantity to decrease to half of its initial value.  The equation to describe the decay is
Nt=N0(1/2) ^{t/t(1/2)}  where N0 is the initial quantity, Nt is the remaining quantity after time t, t1/2 is the half-time.  So work out the equation, t1/2 = t (-ln2)/ln(Nt/N0) = 11.5*(-ln2)/ln(12.5/100) = 3.83 days
5 0
3 years ago
Calculate the solubility of ( = ) in moles per liter. Ignore any acid–base properties. s = mol/L Calculate the solubility of ( =
BaLLatris [955]

This is an incomplete question, here is a complete question.

Calculate the solubility of each of the following compounds in moles per liter. Ignore any acid-base properties.

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Explanation :

As we know that CaCO₃ dissociates to give Ca^{2+} ion and CO_3^{2-} ion.

The solubility equilibrium reaction will be:

CaCO_3\rightleftharpoons Ca^{2+}+CO_3^{2-}

The expression for solubility constant for this reaction will be,

K_{sp}=[Ca^{2+}][CO_3^{2-}]

Let solubility of CaCO₃ be, 's'

K_{sp}=(s)\times (s)

K_{sp}=s^2

8.7\times 10^{-9}=s^2

s=9.33\times 10^{-5}mol/L

Therefore, the solubility of CaCO₃ is, 9.33\times 10^{-5}mol/L

4 0
3 years ago
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During translation, the new polypeptides are often directed to specific parts of the cell by the presence or absence of short se
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Answer:

The correct option is b. an amino-terminal signal

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6 0
2 years ago
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