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Ludmilka [50]
4 years ago
9

Fill in the blanks with the correct word. During diffusion, molecules move from areas of concentration to areas of Diffusion doe

s not require to move molecules. concentration. Previous Activity
TRY A LITTLE -_-
Will give brainliest :)​

Chemistry
1 answer:
stellarik [79]4 years ago
5 0

Answer:

1) higher

2) lower

1) energy

Explanation:

hope this helps you.

I would really like a brainliest :D

thank you and have a nice day.

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Based on the table, which atom has a charge of –1?<br> 1<br> 2<br> 3<br> 4
Shkiper50 [21]

An electron

there is no table but an electron has a charge of -1

<h2>Hope this helps ;D</h2><h2></h2><h2>Kenny </h2>
6 0
3 years ago
What is the ratio of Fe+3 ions to O2- ions in a neutral compound?
SpyIntel [72]

In a neutral compound, the charges must balance, the net charge should be zero.

Since the charge of Fe is 3+ and that of O is 2-, therefore, there should be 2 Fe 3+ ions per 3 O2- ions in order to have a net charge of zero. 

7 0
3 years ago
Read 2 more answers
How many molecules are in 0.25 mole of O2
ziro4ka [17]
1 mole O2 -------------------- 6,02.10²³ molecules
0,25 mole O2 ---------------- x molecules

1 . x = 0,25 . 6,02.10²³

x = 1,50.10²³ molecules


5 0
3 years ago
In an electrolytic cell, where does the oxidation occur? a anode b cathode c external power source d salt bridge
Ganezh [65]
The anode is charged positively. Oxidation happens on the anode.

For example,

(anode +) Zn - 2e⁻ = Zn²⁺
8 0
4 years ago
How many atoms are there in each of the following
oee [108]
<h3>Answer:</h3><h3>a) 9.033 × 10²³ particles</h3><h3>b) 4.068 × 10²⁴ particles</h3><h3>c) 1.51 × 10²³ particles</h3>

Explanation:

For us to answer these questions, we have to know two formulas:

  1. Number of particles = moles × Avogadro's Number
  2. Moles = Mass ÷ Molar Mass

Therefore:

a) particles of Na = 1.50 mol × (6.022 × 10²³) particles/mol

                            = 9.033 × 10²³ particles

b) particles of Pb = 6.755 mol × (6.022 × 10²³) particles/mol

                            = 4.068 × 10²⁴ particles

c) particles of Si

             = (7.02 g ÷ 28.085 g/mol) × (6.022 × 10²³) particles/mol

             = 1.51 × 10²³ particles

                           

4 0
2 years ago
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