The peptide given above is made up of the following amino acids: glycine [G], leucine [L], valine [V], isoleucine [I] and tryptophan [W]. These amino acids are joined together by amide bond to form peptide. Peptides usually have two terminals, the N terminal and the C terminal. For GLVIW, the C terminal end amino acid is tryptophan, that is the last amino acid on the peptide chain. The N terminal amino acid is glycine, that is, the first amino acid on the peptide chain.
(a) The molecular shapes of cis and Trans forms of N2F2 are-
b) There is EN difference between N atom and F atom. Hence the molecule will have a bond dipole.
In Cis form two fluorine atoms are on the same side of N N bond. Hence, bond moment in N2F2 cis form) do not cancel each other. Thus the cis form is polar.
In the trans form two fluorine atoms are on the opposite side of N-N bond. Bond moment of NF cancels each other.
Thus: trans N2F2 is non polar molecule.
Beryllium fluoride I believe is the correct answer
Answer:
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