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alexira [117]
3 years ago
5

2 molecules of Acetaldehyde can only be made from which of these alkenes?

Chemistry
1 answer:
Luba_88 [7]3 years ago
6 0
2 molecules of Acetaldehyde is the product of a reaction of an alkene. One way in which alkenes can react to give carbonyl compounds (ketones/aldehydes) is the reaction with ozone, O₃. The ozonolysis of an alkene will result in cleavage of the carbon-carbon double bond and each carbon that was part of the alkene, will now have a double bond to oxygen. Each carbon of the original alkene will now be a carbonyl in the product.

To form 2 molecules of acetaldehyde, we must cleave an alkene that has the same substitution pattern on each side of the alkene so that the carbonyl compounds formed are identical. Therefore, both (E)- and (Z)-2-butene will react with ozone to give acetaldehyde. The scheme provided shows the reaction of both alkenes to give the acetaldehyde. The products are drawn in such a way to show which part of the original molecules they were derived from. However, both reactions do provide identical products.

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3 years ago
How many grams of neutral salt will be obtained in the reaction of calcium oxide with 200 cm 3 of phosphoric acid solution whose
katen-ka-za [31]

Answer:

9.3 g of Ca3(PO4)2

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

3CaO + 2H3PO4 —> Ca3(PO4)2 + 3H2O

Next, we shall determine the number of mole of H3PO4 present in 200 cm³ of 0.3 mol/dm³ phosphoric acid (H3PO4) solution. This can be obtained as follow:

Molarity of H3PO4 = 0.3 mol/dm³

Volume = 200 cm³ = 200 cm³/1000 = 0.2 dm³

Mole of H3PO4 =?

Molarity = mole /Volume

0.3 = mole of H3PO4 /0.2

Cross multiply

Mole of H3PO4 = 0.3 × 0.2

Mole of H3PO4 = 0.06 mole

Next, we shall determine the number of mole of the salt, Ca3(PO4)2, obtained from the reaction. This can be obtained as shown below:

3CaO + 2H3PO4 —> Ca3(PO4)2 + 3H2O

From the balanced equation above,

2 moles of H3PO4 reacted to produced 1 mole of Ca3(PO4)2.

Therefore, 0.06 moles of H3PO4 will react to produce = (0.06 × 1)/2 = 0.03 mole of Ca3(PO4)2.

Thus, 0.03 mole of Ca3(PO4)2 is produced from the reaction.

Finally, we shall determine the mass of Ca3(PO4)2 produced as follow:

Mole of Ca3(PO4)2 = 0.03 mole

Molar mass of Ca3(PO4)2 = (40×3) + 2[31 + (16×4)]

= 120 + 2[31 + 64]

= 120 + 2[95]

= 120 + 190

= 310 g/mol

Mass of Ca3(PO4)2 =?

Mole = mass /Molar mass

0.03 = mass of Ca3(PO4)2 / 310

Cross multiply

Mass of Ca3(PO4)2 = 0.03 × 310

Mass of Ca3(PO4)2 = 9.3 g

Thus, 9.3 g of Ca3(PO4)2 was obtained from the reaction.

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Answer:

Explanation:

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