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coldgirl [10]
2 years ago
10

If you had a 4.0M and a 0.4M solution of nitric acid, which would have a lower pH? Why?

Chemistry
1 answer:
galina1969 [7]2 years ago
5 0

Answer:

the second one would have lower

Explanation:

because of the amount

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What is the empirical formula for a compound that is 31.9% potassium, 28.9% chlorine, and 39.2% oxygen?
notsponge [240]
The  empirical formula  for a compound   is KClO3

     Explanation 
 
find  the  moles of each  element
moles  = % composition/molar  mass

molar  mass of  of  potassium =39g/mol ,chlorine = 35.5 g/mol, oxygen =16 g/mol

moles  of potassium  =  31.9 / 39 = 0.818  moles
moles of  chlorine    = 28.9/35.5 = 0.814 moles
moles of   oxygen  =  39.2/  16 =  2.45  moles


find the  mole ratio  by  dividing   with  the smallest  mole = 0.814  moles

potassium = 0.818/0.814  =1  
chlorine  =  0.814/0.814 = 1
oxygen =  2.45 /0.814 =3 


the empirical  formula   is therefore = KClO3
7 0
3 years ago
Calculate the equilibrium constant of the reaction below if the pressures are 1.0atm, 2.0 atm, and 1.0 atm respectively. PCl3 +
Makovka662 [10]

Answer:

K = 0.5

Explanation:

Based on the reaction:

PCl₃ + Cl₂ ⇄ PCl₅

The equilibrium constant, K, is defined as:

K = P PCl₅ / P PCl₃ * P Cl₂

<em>Where P represent the pressure at the equilibrium for each one of the gases involved in the equilibrium.</em>

<em />

As:

P PCl₅ = 1.0atm

P PCl₃ = 1.0atm

P Cl₂ = 2.0atm

K = 1.0atm / 1.0atm * 2.0atm

<h3>K = 0.5</h3>
7 0
2 years ago
Which of the following is included in the measure of U.S. GDP?
finlep [7]

the value of increase in business inventories.

7 0
3 years ago
What are 4 examples of sediment that may become sedimentary rock
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7 0
3 years ago
Concentrated HCl is 15 M (15 molar). A 500 mL quantity of this solution is diluted by adding water to give a final volume of 2.5
Murrr4er [49]

The molarity of the resulting solution obtained by diluting the stock solution is 3 M

<h3>Data obtained from the question </h3>
  • Molarity of stock solution (M₁) = 15 M
  • Volume of stock solution (V₁) = 500 mL
  • Volume of diluted solution (V₂) = 2.5 L = 2.5 × 1000 = 2500 mL
  • Molarity of diluted solution (M₂) =?

<h3>How to determine the molarity of diluted solution </h3>

M₁V₁ = M₂V₂

15 × 500 = M₂ × 2500

7500 = M₂ × 2500

Divide both side by 2500

M₂ = 7500 / 2500

M₂ = 3 M

Thus, the volume of the resulting solution is 3 M

Learn more about dilution:

brainly.com/question/15022582

#SPJ1

7 0
1 year ago
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