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saul85 [17]
3 years ago
7

How many students voted

Mathematics
1 answer:
Ivahew [28]3 years ago
5 0

Answer:

Voted for what exactly? I could help you more if you had a more definitive question. Unfortunately, I cannot answer this for you.

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I do not understand
Ivenika [448]
A) 1
B) 10/3
C) 6
D) 18/5
So only C is bigger than 4
4 0
2 years ago
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I don't know how to do this one. plz help
egoroff_w [7]

Answer:

As x decreases without bound, f(x) increases without bound

As x increases without bound, f(x) approaches 0

Step-by-step explanation:

As x gets more and more negative f(x)  gets bigger and bigger

f(x) = (7/10) ^ x but x is negative  so flip it and then x is a larger number

       (10/7) ^  large number   so it will get larger

 as → -∞   f(x) →∞    


As x gets more and more positive f(x)  gets smaller and smaller

f(x) = (7/10) ^ x   closer and closer to 0.  The denominator gets larger faster than the numerator  = 1 / large number

       

 as → ∞   f(x) →0    

3 0
3 years ago
Solve 73 make sure to also define the limits in the parts a and b
Aleks04 [339]

73.

f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}

a)

\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3

b)

Since we can't divide by zero, we need to find when:

x^4-2x^2+144=0

But before, we can factor the numerator and the denominator:

\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}

Now, we can conclude that the vertical asymptotes are located at:

\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}

so, for x = -3:

\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty

For x = 4:

\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty

4 0
1 year ago
Find the total cost. $50 item; $10 coupon off; 10% sales tax
ExtremeBDS [4]

Answer: 44 dollars

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
PLEASE HELP WILL GIVE BRAINLIEST!
NeX [460]
It has to be B since it shoes both boys and girls.
7 0
2 years ago
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