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damaskus [11]
3 years ago
14

Immanuel is building a fence to make an enclosed play area for his dog. The enclosed area will be in the shape of a triangle wit

h a base of 48m and an altitude of 32m. How much space does the dog have to play?
Mathematics
1 answer:
zysi [14]3 years ago
8 0

The area (A) of a triangle is given by the formula

A=\dfrac{1}{2}bh

where b is the length of the base (48 m) and h is the altitude (32 m). Filling in the numbers, we compute the area to be

A=\dfrac{1}{2}\cdot (48\,m)\cdot (32\,m)=768\,m^2

The dog's play space is 768 square meters.

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finlep [7]

Answer:

Coordinates of point B are (10,-4)

Coordinates of point D are (3.6,-0.4)

Step-by-step explanation:

1) Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are ____

Let the coordinates of B be (x_2,y_2)

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Coordinates of C=(x,y)=(3.6,-0.4)

We will use section formula over here

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3.6=\frac{3x_2+2(-6)}{3+2} , -0.4=\frac{3y_2+2(5)}{3+2}3.6 \times 5 = 3x_2-12, -0.4 \times 5 = 3y_2+10\\18+12=3x_2 , -2=3y_2+10\\30=3x_2 , -12=3y_2\\10=x_2, -4=y_2\\

Coordinates of B = (10,-4)

2)If point D divides in the ratio 4 : 5, the coordinates of point D are ____

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Let the coordinates of D be (x,y)

Coordinates of A =(x_1,y_1)=(-6,5)

Coordinates of B=(x_2,y_2)=(10,-4)

We will use section formula over here

x=\frac{mx_2+nx_1}{m+n} , y = \frac{my_2+ny_1}{m+n}

m:n=3:2

x=\frac{3(10)+2(-6)}{3+2} , y=\frac{3(-4)+2(5)}{3+2}\\x=3.6,y=-0.4

Coordinates of point B are (10,-4)

Coordinates of point D are (3.6,-0.4)

4 0
2 years ago
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Answer:

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