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damaskus [11]
3 years ago
14

Immanuel is building a fence to make an enclosed play area for his dog. The enclosed area will be in the shape of a triangle wit

h a base of 48m and an altitude of 32m. How much space does the dog have to play?
Mathematics
1 answer:
zysi [14]3 years ago
8 0

The area (A) of a triangle is given by the formula

A=\dfrac{1}{2}bh

where b is the length of the base (48 m) and h is the altitude (32 m). Filling in the numbers, we compute the area to be

A=\dfrac{1}{2}\cdot (48\,m)\cdot (32\,m)=768\,m^2

The dog's play space is 768 square meters.

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Please help
Harrizon [31]

Answer:

(-1/2, 3/4)

Step-by-step explanation:

Let's use the elimination by adding or subtracting method.  Note that we have 8y in the first equation, and that we could obtain -8y in the second equation by multiplying the second equation by 2:

2(24x - 4y = -15) => 48x - 8y = -30

Now combine this result (this equation) with the first equation:

  2x + 8y = 5

+48x   -8y = -30

---------------------

 50x    =     - 25

Dividing both sides by 50, to isolate x, we get

x = -25/50 = -1/2.

Now substitute -1/2 for x in the first equation and solve the resulting equation for y:

  2x + 8y = 5

2(-1/2) + 8y = 5, or -1 + 8y = 5, or 8y = 6 (after having added 1 to both sides)

Dividing both sides of 8y = 6 by 8 leads to determining the value of y:

y = 6/8 = 3/4

The solution is (-1/2, 3/4).

3 0
3 years ago
HELP DUE in 20 MIN<br> m∠16 =
Ierofanga [76]

9514 1404 393

Answer:

  ∠16 = 47°

Step-by-step explanation:

Vertical and corresponding angles are congruent. The remainder are supplementary to those.

∠1≅∠4≅∠5≅∠7≅∠10≅∠12≅∠13≅∠15 = 133°

∠2≅∠3≅∠6≅∠8≅∠9≅∠11≅∠14≅∠16 = 47°

8 0
2 years ago
C = k - 273.15 (a) Write two other related equations . (b) If the temperature is 23 in degrees Celsius , what is the temperature
Alona [7]

Answer:

(a) k = C + 273.15, F = 1.8(k - 273.15) + 32

(b) k = 296.15

(c) 25 celcius is greater than 300 kelvis.

Step-by-step explanation:

(a) one equation would be to solve for k instead of c, and another related equation could be from kelvin to Farenheit.

C = k - 273.15

C + 273.15 = k

k = C + 273.15

F = 1.8(k - 273.15) + 32

(b) for this one you have to substitute in the previous equation and solve for k.

23 = k - 273.15

k = 23 + 273.15

k = 296.15

(c) you have to convert either kelvins to celcius or celcius to kelvins.

C = k - 273.15

C = 300 - 273.15

C = 26.85

So 25 celcius is greater than 300 kelvis.

5 0
3 years ago
Which inequality is shown in the accompanying diagram?
Olegator [25]

Answer:

Step-by-step explanation:

3 0
3 years ago
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At a cafe, for every 8 hot dogs sold there are 11 hamburgers sold. What is the ratio of hot dogs sold to hamburgers sold?
Bezzdna [24]
I think 8:11 will be the answer
7 0
3 years ago
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