Question

The body of a 154 pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum. Based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body

Answer 1

let a be aluminum and g be gold and k how many times:

2*10⁻¹mg a+ 6*10¹mg g= 154 lb

so a=kg

k=a/g

k=2*10⁻¹/6*10=1/300

a=1/300g

so Aluminum is 1/300 of gold.