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Gnesinka [82]
4 years ago
15

An athlete eats 45 g of protein per day while training. How much protein will she eat during 17 days of training?

Mathematics
2 answers:
astra-53 [7]4 years ago
8 0
The answer to your question is
\boxed {\bf 765g~of~protein}


\bf Explanation:
45(g's~per~day)*17(days~of~training) = 765g

I hope this helps you!
My name is Ann [436]4 years ago
3 0
She eats 45 grams of proteins per day. There is 17 days.

Multiply the two numbers together.

45 x 17 = 765.

the Athlete eats 765 grams of protein during those 17 days of training.


hope this helps
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Length of the bottom of the triangle = x
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6 0
3 years ago
What’s the answer for 9x = 72
aleksklad [387]

Answer:8

Step-by-step explanation: Since the opposing way of solving is division, you divide 72 into 9 and you get 8.

7 0
3 years ago
the spoke of a wheel reaches from the center of the wheel to its rim. If the circumstances of the rim of the wheel is 42 inches,
jekas [21]
The spoke of the wheel serves as the radius of the circle. 
To solve for the circumference of the circle, we use this formula:

C = 2πr
42 inches = 2 * 3.14 * r
42 inches = 6.28 * r
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4 0
3 years ago
Consider a bag of jelly beans that has 30 red, 30 blue, and 30 green jelly beans. a) How many color combinations of 15 beans hav
igor_vitrenko [27]

Answer:

680

Step-by-step explanation:

Number of red beans = 30

Number of Blue beans = 30

Number of green beans = 30

How many color combinations of 15 beans have at least 6 green beans?

Since at least 6 of the beans must be green,

Then (15 - 6) = 9

Then, the remaining 9 could be either red, blue or green.

Therefore, C(9 + (9 - 1), 3)

C(17, 3) = 17C3

nCr = n! ÷ (n-r)! r!

17C3 = 17! ÷ (17 - 3)! 3!

17C3 = 17! ÷ 14!3!

17C3 = (17 * 16 * 15) / (3 * 2)

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5 0
3 years ago
PLEASSSEEEE HELLLLP MEEEE!
Vanyuwa [196]

Answer:

1) C = 3

2) B = 5

3) C = 8

Step-by-step explanation:

Question 1)

We have:

(2x+3)(4x-1)

Distribute:

=(2x+3)(4x)+(2x+3)(-1)

Distribute:

=8x^2+12x-2x-3

Combine like terms:

=8x^2+10x-(3)

Therefore, C = 3.

Question 2)

We have:

(x+2) (2x^2+x-1)

Distribute:

\displaystyle =(x+2)(2x^2)+(x+2)(x)+(x+2)( - 1)

Distribute:

=(2x^3+4x^2)+(x^2+2x)+(-x -2)

Combine like terms:

=2x^3+(5)x^2+x-2

Therefore, B = 5.

Question 3)

We have:

(x+2)(x^2-3x-2)

Distribute:

=(x+2)(x^2)+(x+2)(-3x)+(x+2)(-2)

Distribute:

=(x^3+2x^2)+(-3x^2-6x)+(-2x-4)

Combine like terms:

=x^3-x^2-(8)x-4

So, C = 8.

6 0
2 years ago
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