3x^2 + 4x - 5 = 0
x = [-b ±√(b^2 - 4ac)]/2a
a = 3
b = 4
c = -5
x = [-4 ±√(16 + 60)]/6
x = [-4 ±√76]/6
x = [-4 ±√(2^2 * 19)]/6
x = [-4 ±2√19]/6
x = [-2 ±√19]/3
x = [-2 + √19]/3
x = [-2 + 4.35]/3
x = 2.35/3
x = 0.78 (rounded to the nearest hundredth)
x = [-2 - ±√19]/3
x = [-2 - 4.35]/3
x = -6.35/3
x = -2.12 (rounded to the nearest hundredth)
<span>∴ x = -2.12 , 0.78 (rounded to the nearest hundredth)</span>
Answer: The new ratio will be 1/4
Explanation: The initial ratio of losses to wins is 3 to 2. If we sum the numer of losses and wins 3 + 2 = 5 games, that means they loss 3 out of 5 games , and they win 2 out of 5 games.
So if they had won twice as many of the games, that is 2*2=4. And since the number of games is the same ( 5 ), then they would have won 4 games and loss only 1.
So the new ratio of losses to wins will be 1 to 4, or expressed in a fraction: 1/4
Answer:
The answer is b
Step-by-step explanation:
(4x+5)(16^2-20x+25)
