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GrogVix [38]
3 years ago
7

A salesperson earns 7.5% commission on each vehicle sold. What price

Mathematics
1 answer:
Eddi Din [679]3 years ago
5 0
Hey there! I’m just going to write out how I would solve this.

3,000=7.5%⋅x
100/7.5=13 1/3
3,000⋅13 1/3=x
x=$40,000
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in sports club there are 800 members . the ratio of soccer members to social members is 5to 3 how many soccer players are there
attashe74 [19]
5:3

5+3=8
8 units

800=8 units
divide oth sides by 8
100=1 units

soccer=5 units=5 times 100=500
social=3 units=3 times 100=300



500 soccer players

5 0
3 years ago
Which is bigger, <br> a) 70% of 300 <br> b) ¼ of 600?<br> ∞Δ∞
Artist 52 [7]
Since 300 is 100%, you treat it as such.

300/(100/70) = 210 (rounded)


You do a similar thing for 600

1/4 of 100 is 25
100/25 = 4
600 / 4 = 150



70% of 300 is more.




4 0
3 years ago
Jace measured a line to be 14 inches long. If the actual length of the line is 13.1 inches, then what was the percent error of t
erica [24]

Answer:

Step-by-step explanation:

dont know sorry

4 0
3 years ago
Read 2 more answers
If f(x) = 2x-5, then f(4) is <br><br>A 3<br>B 5<br>C 4<br>D 17​
Ivahew [28]

Answer:

A. 3

Step-by-step explanation:

f(x) = 2x - 5

f(4) = 2(4) - 5

f(4) = 8 - 5

f(4) = 3

5 0
3 years ago
Read 2 more answers
) An amphibious vehicle requires 5 minutes to travel each mile over land, but only 4 minutes to travel each mile in the water. T
tangare [24]

Answer:

x = 0.63 miles

y = 3.10 miles

Step-by-step explanation: See Annex

Vehicle capacities.

In land 1 mile in 5 minutes    then   1/5 mile in 1 minute

In water 1 mile in 4 minutes   then  1/4 mile in 1 minute

Let call x the number of miles in water and y the number of miles in land

Then the route will be x (miles in water ) and y miles in land

From Annex

L = 1/4*x + 1/5*y

From Figure (Annex) y = √( 3 - x )² + ( 2)² Pithagoream theorem

y = √ 9 + x² -6*x + 4 ⇒ y = √ x² - 6*x + 13  

Then

L(x) = 1/4x + 1/5√ x² - 6*x + 13  

Taking derivatives on both sides of the equation:

L´(x) = 1/4 + 1/5* 1/2 (2*x -6) / √ x² - 6*x + 13  

L´(x) = 0 ⇒ 1/4 + 1/5* 1/2 (2*x -6) / √ x² - 6*x + 13 = 0

[1/4* √( x² - 6*x + 13) + 1/5* (x -3) ] /√ x² - 6*x + 13 = 0  

1/4* √( x² - 6*x + 13) + 1/5*x - 3/15 = 0      ⇒ 1/4* √( x² - 6*x + 13)  = 1/5  ( x -3)

1/4* √( x² - 6*x + 13) = 1/5*x  - 1/5      

Squaring both sides

1/16* (x² - 6*x + 13) = 1/25 (x - 3 )²   ⇒   x²/16  - 6/16 *x + 13/16 = 1/25 ( x² + 9 - 6*x

25 (x² - 6*x + 13)  = 16 ( x² + 9 -6*x)

25*x² - 150*x +  325  =  16x² + 144 - 96*x

9*x² - 294*x + 181 =  0

x₁,₂  =  294 ± √ (86436 -  6516) / 18

x₁   =  294 +  282,7 / 18      we dismiss that solution si not feasible with problem statemente

x₂ = 294 - 282,7 / 18

x₂ = 11.3/ 18

x₂ =  0.63 miles      and  y =  √ x² - 6*x + 13     ⇒    y  = 3.10 miles

8 0
3 years ago
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