Answer:
Step-by-step explanation:
eq. of line parallel to AB is y=2x+a
if it passes through (3,-2) then
-2=2×3+a
a=-2-6=-8
y=2x-8
Answer:
![W=\{\left[\begin{array}{ccc}a+2b\\b\\-3a\end{array}\right]: a,b\in\mathbb{R} \}](https://tex.z-dn.net/?f=W%3D%5C%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%2B2b%5C%5Cb%5C%5C-3a%5Cend%7Barray%7D%5Cright%5D%3A%20a%2Cb%5Cin%5Cmathbb%7BR%7D%20%5C%7D)
Observe that if the vector
is in W then it satisfies:
![\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{c}a+2b\\b\\-3a\end{array}\right]=a\left[\begin{array}{c}1\\0\\-3\end{array}\right]+b\left[\begin{array}{c}2\\1\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Da%2B2b%5C%5Cb%5C%5C-3a%5Cend%7Barray%7D%5Cright%5D%3Da%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D1%5C%5C0%5C%5C-3%5Cend%7Barray%7D%5Cright%5D%2Bb%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D2%5C%5C1%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
This means that each vector in W can be expressed as a linear combination of the vectors ![\left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D1%5C%5C0%5C%5C-3%5Cend%7Barray%7D%5Cright%5D%2C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D2%5C%5C1%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
Also we can see that those vectors are linear independent. Then the set
is a basis for W and the dimension of W is 2.
The tank is leaking at the rate of 6 gallons per hour.
If you do nothing but sit there and watch it all afternoon,
here's what you'll see:
First hour . . . . 6 gallons leaks out
Second hour . another 6 gallons leaks out
Third hour . . . another 6 gallons leaks out
Total gone after 3 hours: (6 + 6 + 6) = 18 gallons .
Solution:
we are given that
Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m^2, and the area of circle R's sector is 49π m^2.
we have been asked to find the ratio of the radius of circle Q to the radius of circle R?
As we know that
Area of the sector is directly proportional to square of radius. So we can write

<span>t+u = 10
10u+t= 10t+u-54
Rearrange:
t+u=10
9t-9u=54
Simplify:
1st; t+u=10
2nd: t-u=6
Add 1st and 2nd and solve for t,as follows:
2t = 16
t = 8
Substitute in t+u=10 to solve for u:
8+u=10
u = 2
Original Number = 82</span>