The answer is $2.89.
Since it’s asking for the unit price of one gallon and you have the total ($34.68 and 12 gallons), you would divide $34.68 from 12, which gives you $2.89.
34.68/12 = 2.89
1ml=1g
85.32ml=85.32g of blood plasma
The balanced reaction equations are;
a) 4 NaClO + H2S → 4 NaCl + H2SO4
b)6Ce^4+ + I^– + 6OH^– → 6 Ce^3+ + IO3^– + 3H2O
<h3>What is a balanced redox reaction?</h3>
A redox reaction is said to be balanced when the number of electrons gained is equal to the number of electrons lost.
Let us now write the balanced reaction equations one after the other. Thus;
a) 4 NaClO + H2S → 4 NaCl + H2SO4
b)6Ce^4+ + I^– + 6OH^– → 6 Ce^3+ + IO3^– + 3H2O
Learn more about redox reaction:brainly.com/question/13293425
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What's the relationship between total and partial pressure? The total pressure is the sum of the parcial pressures!
So for us, it would be:
378= 212+101+x
where x is the parcial pressure of nitrogen.
Now we count:
378= 212+101+x
378=313+x
378-313=x
65=x
So the parcial pressure exerted by nitrogen is 65!
Complete Question:
Ions to calculate the p-values: Na⁺, Cl⁻, and NH₄⁺
Answer:
pNa = 0.307
pCl = 0.093
pNH₄ = 0.503
Explanation:
The p-value is calculated by the antilog of the concentration of the substance of interest. For example, pH = -log[H⁺]. Thus, first, let's find the ions concentration.
Both substances are salts that solubilize completely, thus, by the solution reactions:
NaCl → Na⁺ + Cl⁻
NH₄Cl → NH₄⁺ + Cl⁻
So, for both reactions the stoichiometry is 1:1:1 and the concentration of the ions is equal to the concentration of the salts.
[Na⁺] = 0.493 M
[Cl⁻] = 0.493 + 0.314 = 0.807 M
[NH₄⁺] = 0.314 M
The p-values are:
pNa = -log[Na⁺] = -log(0.493) = 0.307
pCl = -log[Cl⁻] = -log(0.807) = 0.093
pNH₄ = -log[NH₄⁺] = -log(0.314) = 0.503