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Reil [10]
3 years ago
8

Net ionic equation for the reaction that occurs, if any, when cesium metal (Z=55) is placed in hydrochloric acid. Cesium metal i

s above hydrogen gas in the activity series?
Chemistry
1 answer:
geniusboy [140]3 years ago
8 0
The chemical activity series is the arrangement of the elements descendingly according to their chemical activity for reactions like simple substitution reactions and redox reactions. Elements above hydrogen can replace hydrogen from water and acids as they are more active than hydrogen. Since cesium is more active than hydrogen, it replaces it in hydrochloric acid.

2 cesium atoms loses 2 electrons first;
2Cs --> 2Cs+ + 2e-

2 hydrogen atoms recieve the two electrons;
2H+ + 2e- --> H2

The net ionic equation is;
2Cs + 2HCl --> CsCl + H2
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If 12 gallons of gasoline cost $34.68, what is the unit price per gallon?
chubhunter [2.5K]
The answer is $2.89.

Since it’s asking for the unit price of one gallon and you have the total ($34.68 and 12 gallons), you would divide $34.68 from 12, which gives you $2.89.

34.68/12 = 2.89
5 0
2 years ago
What is the mass in grams of 85.32 mL of blood plasma
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1ml=1g
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7 0
3 years ago
5. Balance the following reactions using either the oxidation number method or the half-reaction
stich3 [128]

The balanced reaction equations are;

a) 4 NaClO + H2S → 4 NaCl + H2SO4

b)6Ce^4+ + I^– + 6OH^– → 6 Ce^3+ + IO3^– + 3H2O

<h3>What is a balanced redox reaction?</h3>

A redox reaction is said to be balanced when the number of electrons gained is equal to the number of electrons lost.

Let us now write the balanced reaction equations one after the other. Thus;

a) 4 NaClO + H2S → 4 NaCl + H2SO4

b)6Ce^4+ + I^– + 6OH^– → 6 Ce^3+ + IO3^– + 3H2O

Learn more about redox reaction:brainly.com/question/13293425

#SPJ1

7 0
2 years ago
A mixture of oxygen, hydrogen, and nitrogen exerts a total pressure of 378 kPa. If the partial pressures of oxygen and hydrogen
sertanlavr [38]
What's the relationship between total and partial pressure? The total pressure is the sum of the parcial pressures!


So for us, it would be:

378= 212+101+x

where x is the parcial pressure of nitrogen.

Now we count:
378= 212+101+x
378=313+x
378-313=x
65=x

So the parcial pressure exerted by nitrogen is 65!

8 0
3 years ago
For each solution, determine the p-values for each ion indicated. A solution that is 0.493 M in NaCl and 0.314 M in NH 4 Cl .
miss Akunina [59]

Complete Question:

Ions to calculate the p-values: Na⁺, Cl⁻, and NH₄⁺

Answer:

pNa = 0.307

pCl = 0.093

pNH₄ = 0.503

Explanation:

The p-value is calculated by the antilog of the concentration of the substance of interest. For example, pH = -log[H⁺]. Thus, first, let's find the ions concentration.

Both substances are salts that solubilize completely, thus, by the solution reactions:

NaCl → Na⁺ + Cl⁻

NH₄Cl → NH₄⁺ + Cl⁻

So, for both reactions the stoichiometry is 1:1:1 and the concentration of the ions is equal to the concentration of the salts.

[Na⁺] = 0.493 M

[Cl⁻] = 0.493 + 0.314 = 0.807 M

[NH₄⁺] = 0.314 M

The p-values are:

pNa = -log[Na⁺] = -log(0.493) = 0.307

pCl = -log[Cl⁻] = -log(0.807) = 0.093

pNH₄ = -log[NH₄⁺] = -log(0.314) = 0.503

7 0
4 years ago
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